1) In a random sample of eight cell phones, the mean full retail price was $526.50...
1) In a random sample of eight cell phones, the mean full retail price was $526.50 and the standard deviation was $184.00. Construct a 95% confidence interval for the true population price. Assume the sample was random and that the population of cell phone prices is normally distributed. Round your final answer to the nearest cent (2 numbers after the decimal)
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1) In a random sample of eight cell phones, the mean full retail
price was $526.50...
In a random sample of eight cell phones, the mean full retail price was $460.00 and...
In a random sample of eight cell phones, the mean full retail price was $460.00 and the standard deviation was $173.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean u. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.) Construct a 95% confidence interval for the population mean. (Round to one decimal place as needed.) Interpret...
In a random sample of eight cell phones, the mean full retail price was $559.00 and...
In a random sample of eight cell phones, the mean full retail price was $559.00 and the standard deviation was $226 00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 99% confidence interval for the population mean Interpret the results o Identify the margin of error (Round to one decimal place as needed) Construct a 99% confidence interval for the population mean IA (Round to one decimal place as...
In a random sample of eleven cell phones, the mean full retail price was $515.50 and...
In a random sample of eleven cell phones, the mean full retail price was $515.50 and the standard deviation was $212.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 90% confidence interval for the population mean mu. Interpret the results.
In a random sample of eleven cell phones, the mean full retail price was $460.50 and...
In a random sample of eleven cell phones, the mean full retail price was $460.50 and the standard deviation was $190.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 90% confidence interval for the population mean mu. Interpret the results. Identify the margin of error.
In a random sample of 7 cell phones, the mean full retail price was $502.40 and...
In a random sample of 7 cell phones, the mean full retail price was $502.40 and the standard deviation was $190.00 Further research suggests that the population mean is $427.17. Does the t-value for the original sample fall between −t 0.99 and t 0.99? Assume that the population of full retail prices for cell phones is normally distributed.
1. A random sample of 50 calls initiated on cell car phones had a mean duration...
1. A random sample of 50 calls initiated on cell car phones had a mean duration of 3.5 Assume the population SD 671.2 min. a) Find a 95% confidence interval for the population mean duration of telephone calls initiated on cell car phone and interpret your result ) Find a 90% confidence interval for the population mean duration of telephone calls itiated on cell car phone. Compare with the result in part a)
i would use a t distribution because its a sample and its normally distrubted, im not...
i would use a t distribution because its a sample and its normally
distrubted, im not sure if thats correct
9. (0 points) Assume that all cell phone prices are normally distributed. In a random sample of 20 cell phones, you find that the mean price was $500 with a standard deviation of $180. If you would like to construct a 95%-confidence interval to estimate the population mean, what distribution would you use to find the margin of error? Explain...
Random sample of 11 completed auctions for phones, sample mean price of 795 and standard deviation...
Random sample of 11 completed auctions for phones, sample mean price of 795 and standard deviation of 22.15. we wish to make a 95% confidence interval for the population mean price, the t-critical value, t .025, is closest to:
A random sample of 49 observations is used to estimate the population variance. The sample mean a...
A random sample of 49 observations is used to estimate the population variance. The sample mean and sample standard deviation are calculated as 59 and 3.1, respectively. Assume that the population is normally distributed. (You may find it useful to reference the appropriate table: chi-square table or F table) a. Construct the 90% interval estimate for the population variance. (Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval b. Construct the...
A random sample of 24 observations is used to estimate the population mean. The sample mean...
A random sample of 24 observations is used to estimate the population mean. The sample mean and the sample standard deviation are calculated as 128.4 and 26.80, respectively. Assume that the population is normally distributed. [You may find it useful to reference the t table.) a. Construct the 95% confidence interval for the population mean. (Round intermediate calculations to at least 4 decimal places. Round "t" value to 3 decimal places and final answers to 2 decimal places.) Confidence interval...
In a random sample of eight cell phones, the mean full retail price was $460.00 and the standard deviation was $173.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean u. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.) Construct a 95% confidence interval for the population mean. (Round to one decimal place as needed.) Interpret...
In a random sample of eight cell phones, the mean full retail price was $559.00 and the standard deviation was $226 00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 99% confidence interval for the population mean Interpret the results o Identify the margin of error (Round to one decimal place as needed) Construct a 99% confidence interval for the population mean IA (Round to one decimal place as...
1. A random sample of 50 calls initiated on cell car phones had a mean duration of 3.5 Assume the population SD 671.2 min. a) Find a 95% confidence interval for the population mean duration of telephone calls initiated on cell car phone and interpret your result ) Find a 90% confidence interval for the population mean duration of telephone calls itiated on cell car phone. Compare with the result in part a)
i would use a t distribution because its a sample and its normally
distrubted, im not sure if thats correct
9. (0 points) Assume that all cell phone prices are normally distributed. In a random sample of 20 cell phones, you find that the mean price was $500 with a standard deviation of $180. If you would like to construct a 95%-confidence interval to estimate the population mean, what distribution would you use to find the margin of error? Explain...
A random sample of 49 observations is used to estimate the population variance. The sample mean and sample standard deviation are calculated as 59 and 3.1, respectively. Assume that the population is normally distributed. (You may find it useful to reference the appropriate table: chi-square table or F table) a. Construct the 90% interval estimate for the population variance. (Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval b. Construct the...
A random sample of 24 observations is used to estimate the population mean. The sample mean and the sample standard deviation are calculated as 128.4 and 26.80, respectively. Assume that the population is normally distributed. [You may find it useful to reference the t table.) a. Construct the 95% confidence interval for the population mean. (Round intermediate calculations to at least 4 decimal places. Round "t" value to 3 decimal places and final answers to 2 decimal places.) Confidence interval...
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