The time needed to complete a statistics test at national level is normally distributed with a mean of 120 minutes (2 hours) and standard deviation of 21 minutes.
Let X be time needed to complete a statistics test at national level.
X is normally distributed with a mean (µ) = 120 minutes (2 hours) and standard deviation (σ) = 21 minutes.
P(120 < X < 150) = P((120 – 120)/21 < (X - µ)/ σ <(150 - 120)/21)
= P(0 < Z < 1.43)
= P(Z ≤ 1.43) – P(Z ≤ 0)
= 0.9236 – 0.5 …… (Using statistical table)
= 0.4236
P(120 <X < 150) = 0.4236
The probability that a student completes a test between two hours (120min) and two hours and half (150min) is 0.4236.
We will solve this problem by standardising.
P( X > 120) = (X - µ)/ σ > (120 - 120)/21
= P(Z > 0)
= 1 - P(Z ≤ 0)
= 1 – 0.5…… (Using statistical table)
= 0.5
The probability that a student completes a stats test in more than 2 hours is 0.5
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