Question

Studies are often done by pharmaceutical companies to determine the effectiveness of a treatment program. Suppose that a new AIDS antibody drug is currently under study. It is given to patients once the AIDS symptoms have revealed themselves. Of interest is the average (mean) length of time in months patients live once starting the treatment. Two researchers each follow a different set of 40 AIDS patients from the start of treatment until their deaths. The following data (in months) are collected. Researcher A: 3; 4; 11; 15; 16; 17; 22; 44; 37; 16; 14; 24; 25; 15; 26; 27; 33; 29; 35; 44; 13; 21; 22; 10; 12; 8; 40; 32; 26; 27; 31; 34; 29; 17; 8; 24; 18; 47; 33; 34 Complete the tables using the data provided: Researcher A Survival Length (in months) Frequency Relative Frequency Cumulative Relative Frequency 0.5–6.5 2 2/40 0.05 6.5–12.5 5 5/40 0.05+0.125=0.175 12.5–18.5 9 9/40

0.175+0.225=0.4 18.5–24.5 5 5/40 0.4+0.125=0.525 24.5–30.5 7 7/40 0.525+0.175=0.7 30.5–36.5 7 7/40 0.7+0.175=0.875 36.5–42.5 2 2/40 8.75+0.05=8.8 42.5–48.5 3 3/40 8.8+0.075=8.875 Answer 1: 2 Answer 2: 2/40 Answer 3: 0.05 Answer 4: 5 Answer 5: 5/40 Answer 6: 0.05+0.125=0.175

My class says my answers are wrong. This differs than the one that is answered on here because there is only one research group, Group A, there is not a Group B

Answer 1

Arrange the data in ascending order and complete the frequency table.

yours mistake is at the length 36.5–42.5 2 2/40 8.75+0.05=8.8 ***( It is 0.875 u have used 8.75)

The frequency table for the survival length of researcher A is as follows

Survival Length	Frequency	Relative Frequency (Frequency/Total)	Cumulative Relative frequency
0.5 - 6.5	2	0.05	0.05
6.5 - 12.5	5	0.125	0.175
12.5 - 18.5	9	0.225	0.4
18.5 - 24.5	5	0.125	0.525
24.5 - 30.5	7	0.175	0.7
30.5 - 36.5	7	0.175	0.875
36.5 - 42.5	2	0.05	0.925
42.5 - 48.5	3	0.075	1
Total	40