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A 25.0 mL volume of 0.0200 M Fe(NO3)3 is mixed with 50.0 mL of 0.00200 M...

A 25.0 mL volume of 0.0200 M Fe(NO3)3 is mixed with 50.0 mL of 0.00200 M NaSCN and 25.0 mL of 0.100 HNO3. The blood-red FeSCN2+ ion forms and the equilibrium is established:

Fe3+(aq) + SCN-(aq) <---> FeSCN2+(aq)

The equilibrium concentration of FeSCN2+ ([FeSCN2+]) was measured spectrophotometrically and found to be 7.0 x 10-4 mol/L. To calculate the equilibrium constant (Kc) for thr equilibrium system, proceed through the following steps:

A. Moles of Fe3+, initial

B. Moles of SCN-, initial

C. Moles of FeSCN2+, at equilibrium

D. Moles of Fe3+, reacted

E. Moles of SCN-, reacted

F. Moles of unreacted Fe3+ (A - D)

G. Moles of unreacted SCN- (B - E)

H. [Fe3+] at equilibrium

I. [SCN-] at equilibrium

J. [FeSCN2+] at equilibrium

K. Kc of FeSCN2+

Please and thank you!

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