Find the electric energy density between the plates of a 225-μF parallel-plate capacitor. The potential difference between the plates is 390 V , and the plate separation is 0.225 mm .
Answer in J/m3.
Find the electric energy density between the plates of a 225-μF parallel-plate capacitor. The potential difference...
Find the electric energy density between the plates of a 225-μF parallel-plate capacitor. The potential difference between the plates is 305 V , and the plate separation is 0.250 mm .
Problem 20.67 PartA Find the electric energy density between the plates of a 225-uF parallel-plate capacitor. The potential difference between the plates is 390 V, and the plate separation is 0.212 mm 3/㎡
(17) A 5.90 μF , parallel-plate, air capacitor has a plate separation of 3.90 mm and is charged to a potential difference of 390 V A) Calculate the energy density in the region between the plates.
1. Calculate the work done by a 8.5-V battery as it charges a 7.5-μF capacitor in the flash unit of a camera. Express your answer using two significant figures. W=?? μJ 2. Find the electric energy density between the plates of a 225-μF parallel-plate capacitor. The potential difference between the plates is 360 V , and the plate separation is 0.261 mm . uE= ?? Jm^3
The electric field in the region between the plates of a parallel plate capacitor has a magnitude of 3.5 105 V/m. If the plate separation is 0.50 mm, determine the potential difference between the plates. _______V
Two identical parallel-plate capacitors, each with capacitance 13.0 μF, are charged to potential difference 47.5 V and then disconnected from the battery. They are then connected to each other in parallel with plates of like sign connected. Finally, the plate separation in one of the capacitors is doubled. (a) Find the total energy of the system of two capacitors before the plate separation is doubled. J (b) Find the potential difference across each capacitor after the plate separation is doubled....
A parallel-plate capacitor (Homework #2) A parallel-plate capacitor is made by a pair of plates with area A and separation d. At first, the plates are charged up to +Q and -O respectively, and then a battery is disconnected. Express all the answers for a) through f) only by Q, d, A and 5 +Q 2d -Q Area A a) What is the electric field E inside of the capacitor? b) What is the potential difference V between the plates?...
The potential difference between the plates of a parallel plate capacitor is 45 V and the electric field between the plates has a strength of 850 V/m. If the plate area is 4.0
A parallel-plate air-filled capacitor having area 31 cm2 and plate spacing 3.0 mm is charged to a potential difference of 400 V. Find the following values. (a) the capacitance pF (b) the magnitude of the charge on each plate nC (c) the stored energy μJ (d) the electric field between the plates V/m (e) the energy density between the plates J/m3
A parallel-plate air-filled capacitor having area 44 cm2 and plate spacing 5.0 mm is charged to a potential difference of 850 V. Find the following values. (a) the capacitance (pF) (b) the magnitude of the charge on each plate (nC) (c) the stored energy (μJ) (d) the electric field between the plates (V/m) (e) the energy density between the plates (J/m3)