Question

Function with Pointer (C++)

1. The function should be named "myFunction" which takes two pointers to chars and returns void (nothing).

2. The value pointed in the first argument should be copied into the value of the second pointer (and the second to the first).

3. The pointer itself is not copied, just the char it points to.

Thanks in advance!

Answer 1

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#include <iostream>

using namespace std;

// The function should be named "myFunction"
// which takes two pointers to chars
// and returns void (nothing).
void myFunction(char*, char*);

int main()
{
// accept the first and second characters
char first, second;
cout << "Enter first character : ";
cin >> first;
cout << "Enter second character : ";
cin >> second;
  
// print the values of the variables before calling function
cout << endl << "Values before copying::" << endl;
cout << "first character = " << first << endl;
cout << "second character = " << second << endl << endl;
  
// call the function by passing the variables first and second
// &first is the address of first and &second is the address of second
myFunction(&first, &second);
  
// print the values of the variables after calling functiona
cout << endl << "Values after copying::" << endl;
cout << "first character = " << first << endl;
cout << "second character = " << second << endl << endl;
return 0;
}

void myFunction(char* c1, char* c2) {
// The value pointed in the first argument
// is copied into the value of the second argument
// and it is done with the help of an intermediate
// temporary variable temp
  
// The pointer itself is not copied, just the char it points to.
// *c1 and *c2 refers the value stored at address c1 and c2 respectively.
char temp;
temp = *c1;
*c1 = *c2;
*c2 = temp;
}
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