Question

Programming in C

Purpose The purpose of the lab is to learn how to pass pointers in C. Process Create the functions as defined in the following table. Each function will add the last two integer parameters together Function PrototypeReturr int add2a(int,int); Returns the sum as a return value void add2b(int* int,int); Returns the sum in the first parameter int add2c(int*,int,int); Returns the sum as a return value and in the first parameter Returns the sum as a pointer to memory dynamically allocated in the function int* add2d(int,int); const int* add2e(int,int); |Returns the sum as a constant pointer to memory dynamically allocated in the function In the main function, demonstrate each of these functions and display their results. Turn in your program as before.

Answer 1

#include <stdio.h>

#include <stdlib.h>

int add2a(int a, int b){

return a+b;

}

void add2b(int *sum, int a, int b){

*sum = a+b;

}

int add2c(int *sum, int a, int b){

*sum = a+b;

return *sum;

}

int * add2d(int a, int b){

int *sum = (int*)malloc(sizeof(int));

*sum = a+b;

return sum;

}

const int * add2e(int a, int b){

int *sum = malloc(sizeof(int));

*sum = a+b;

return sum;

}

int main() {

int result;

int *sum = &result;

printf("add2a = %d\n",add2a(2,3));

add2b(sum,2,3);

printf("add2b = %d\n",result);

int p = 5, q = 9;

printf("add2c = %d\n",add2c(sum,p,q));

p = 11, q = 20;

sum = add2d(p,q);

printf("add2d = %d\n",*sum);

p = 10, q = 12;

const int *ptr = add2e(p,q);

printf("add2e = %d\n",*ptr);

return 0;

}

=====================================================================
SEE OUTPUT

main.c saved clang version .0.0-3ubunt al) add2a5 add2b5 add2c 14 add2d- 31 add2e- 22 Files 21 22 E const int add2e(int a, int b) 23 int *summalloc(sizeof (int)); 24. 25 26 27 int main() { 28int result; 29 30 printf("add2a =%d\n",add2a (2,3)); 31 32 printf("add2b =%d\n",result ) ; main.c *suma+b; return sum; int *sum&result; add2b (sum,2,3); 34 35 36 37 38 39 40 41 42 43 int p 5, q-9; printf("add2c- %d\n",add2c(sum , p , q )); p 11, q20; sum-add2d (p,q); printf("add2d- %d\n",*sum); p = 10, q = 12; const int *ptradd2e (p,q); printf("add2e- %d\n" , *ptr); return 0; 45


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