A 1.2 m long thin rod is pivoted to rotate <!- out an axis 15 cm...
A 1.2 m long thin rod is pivoted to rotate <!- out an axis 15 cm from the end. If the rod's mass is 250 g, what is the moment of inertia of the thin rod about this, horizontal.axis? the correct answers 0.0806 kg*m^2 show why and how
Homework Answers
iz ML?.ro If a thin rod with mass M and length L is pivoted at the...
iz ML?.ro If a thin rod with mass M and length L is pivoted at the center of mass and free to rotate. At this condition the moment of inertia of the thin rod is ICM = If the 12 same rod is pivoted L/6 away from its center of mass the new moment of inertia of the rod is INEW. What is the ratio of INEW/ICM? Round of your answer to two decimal places
A thin uniform rod (length = 1.77 m, mass = 3.13 kg) is pivoted about a...
A thin uniform rod (length = 1.77 m, mass = 3.13 kg) is pivoted about a horizontal frictionless pin through one of its ends. The moment of inertia of the rod through this axis is (1/3)mL2. The rod is released when it is 58.5° below the horizontal. What is the angular acceleration of the rod at the instant it is released? (in rad/s^2) A: 2.712 B: 3.173 C: 3.713 D: 4.344 E: 5.082 F: 5.946 G: 6.957 H: 8.140
A thin uniform rod (mass= 4.0 kg, length= 120.cm) rotates about an axis that is perpendicular...
A thin uniform rod (mass= 4.0 kg, length= 120.cm) rotates about an axis that is perpendicular to the rod; the axis intersects the rod at 1/3 of the rod's length. The rod rotates about the axis at the rate of 8 full revolutions per second. a. Compute the rotational Inertia of the rod based on the given axis of rotation. b. Compute the magnitude of the angular velocity in radians per second c. Compute the tangential speed of the end...
A very thin, straight, uniform rod has a length of 3.00 m and a total mass...
A very thin, straight, uniform rod has a length of 3.00 m and a total mass of 7.00 kg. Treating the rod as essentially a line segment of mass (distributed uniformly), do the following: (i) Use integration to prove that the rod's center of mass is located at its center point. (Reminders: dmnds mass (and that axis is perpendicular to the rod). with the previous result-to calculate lemr the moment of inertia of the rod about an axis through one...
1. a. A very thin, straight, uniform rod has a length of 3.00 m and a...
1. a. A very thin, straight, uniform rod has a length of 3.00 m and a total mass of 700 kg. Treating the rod as essentially a line segment of mass (distributed uniformly), do the following: (i) Use integration to prove that the rod's center of mass is located at its center point. ii) Now use integration to calculatethe moment of inertia of the rod about an axis through that center of (ii) Now use two different methods-first by direct...
Two masses my and my are attached to a rod that is capable of rotating about...
Two masses my and my are attached to a rod that is capable of rotating about an axis perpendicular to the rod and passing through the end A as shown in the diagram below. The length of the rod is L = 17.0 cm, mı = 2.00 g, m2 = 3.50 9, X1 = 5.40 cm and x2 = 8.55 cm. L m m A X2 *1 (a) What is the moment of inertia of the system about the specified...
A thin uniform rod has a length of 0.550 m and is rotating in a circle on a frictionless table. The axis of rotation is perpendicular to the length of the rod at one end and is stationary.
A thin uniform rod has a length of 0.550 m and is rotating in a circle on a frictionless table. The axis of rotation is perpendicular to the length of the rod at one end and is stationary. The rod has an angular velocity of 0.42 rad/s and a moment of inertia about the axis of 2.60x10-3 kg .m2 . A bug initially standing on the rod at the axis of rotation decides to crawl out to the other end...
A uniform thin rod of length 50 cm and mass 4.0 kg can rotate in a...
A uniform thin rod of length 50 cm and mass 4.0 kg can rotate in a horizontal plane about a vertical axis through from the right side. The rod into one end of the rod. As viewed from above, the bullet's path makes an angle of θ 60° with the rod (as shown in the figure below)If the bullet lodges in the rod and the angular velocity of the rod is 10 rad/s immediately after the collision, what is the...
1. Finding the Moment of Inertia of a Uniform Thin Rod with mass M and length...
1. Finding the Moment of Inertia of a Uniform Thin Rod with mass M and length L rotating about its center (a thin rod is a ID object; in the figure the rod has a thickness for clarity): For this problem, use a coordinate axis with its origin at the rod's center and let the rod extend along the x axis as shown here (in other problems, you will need to generate the diagram): dx dm Now, we select a...
A thin uniform rod has a length of 0.530 m and is rotating in a circle...
A thin uniform rod has a length of 0.530 m and is rotating in a circle on a frictionless table. The axis of rotation is perpendicular to the length of the rod at one end and is stationary. The rod has an angular velocity of 0.41 rad/s and a moment of inertia about the axis of 3.10×10−3 kg⋅m2 . A bug initially standing on the rod at the axis of rotation decides to crawl out to the other end of...
iz ML?.ro If a thin rod with mass M and length L is pivoted at the center of mass and free to rotate. At this condition the moment of inertia of the thin rod is ICM = If the 12 same rod is pivoted L/6 away from its center of mass the new moment of inertia of the rod is INEW. What is the ratio of INEW/ICM? Round of your answer to two decimal places
A thin uniform rod (mass= 4.0 kg, length= 120.cm) rotates about an axis that is perpendicular to the rod; the axis intersects the rod at 1/3 of the rod's length. The rod rotates about the axis at the rate of 8 full revolutions per second. a. Compute the rotational Inertia of the rod based on the given axis of rotation. b. Compute the magnitude of the angular velocity in radians per second c. Compute the tangential speed of the end...
A very thin, straight, uniform rod has a length of 3.00 m and a total mass of 7.00 kg. Treating the rod as essentially a line segment of mass (distributed uniformly), do the following: (i) Use integration to prove that the rod's center of mass is located at its center point. (Reminders: dmnds mass (and that axis is perpendicular to the rod). with the previous result-to calculate lemr the moment of inertia of the rod about an axis through one...
1. a. A very thin, straight, uniform rod has a length of 3.00 m and a total mass of 700 kg. Treating the rod as essentially a line segment of mass (distributed uniformly), do the following: (i) Use integration to prove that the rod's center of mass is located at its center point. ii) Now use integration to calculatethe moment of inertia of the rod about an axis through that center of (ii) Now use two different methods-first by direct...
Two masses my and my are attached to a rod that is capable of rotating about an axis perpendicular to the rod and passing through the end A as shown in the diagram below. The length of the rod is L = 17.0 cm, mı = 2.00 g, m2 = 3.50 9, X1 = 5.40 cm and x2 = 8.55 cm. L m m A X2 *1 (a) What is the moment of inertia of the system about the specified...
A uniform thin rod of length 50 cm and mass 4.0 kg can rotate in a horizontal plane about a vertical axis through from the right side. The rod into one end of the rod. As viewed from above, the bullet's path makes an angle of θ 60° with the rod (as shown in the figure below)If the bullet lodges in the rod and the angular velocity of the rod is 10 rad/s immediately after the collision, what is the...
1. Finding the Moment of Inertia of a Uniform Thin Rod with mass M and length L rotating about its center (a thin rod is a ID object; in the figure the rod has a thickness for clarity): For this problem, use a coordinate axis with its origin at the rod's center and let the rod extend along the x axis as shown here (in other problems, you will need to generate the diagram): dx dm Now, we select a...
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