Question

How to extract the date and ip address of a string in java using regex.

Example:

10.223.157.186 - - [15/Jul/2009:14:58:59 -0700] "GET / HTTP/1.1" 403 202

given an input like the string above, I want to extract the ip address and the date so that the output is:

Ip address: 10.223.157.186

Date: 15/Jul/2009:14:58:59

Answer 1

Code :

package ip_date_regex;

import java.util.ArrayList;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class IP_DATE_regex {

private static Pattern IP_PTN = Pattern.compile("(d{1,3}).(d{1,3}).(d{1,3}).(d{1,3})");//regular expression for ip address
private static Pattern DATE_PTN= Pattern.compile("[0-9]{1,2}/(?:Jan|Feb|Mar|Apr|May|June?|July?|Aug|Sept?|Oct|Nov|Dec)/dddd:(00|[0-9]|1[0-9]|2[0-3]):([0-9]|[0-5][0-9]):[0-59]{1,2}");//regular expression for date

public static List<String> FindIpAdress(String Text)//method(function) for match or find ip address
{
Matcher match = IP_PTN.matcher(Text);
List<String> ipadd = new ArrayList<String>();
while(match.find())
{
ipadd.add(match.group());//if find matching,store in ipadd until all matches found
}
return ipadd;
}
  
public static List<String> FindDate(String Text)//method(function) for match or find date
{

Matcher match = DATE_PTN.matcher(Text);
List<String> date = new ArrayList<String>();
while(match.find())
{
date.add(match.group());//if find matching,store in date until all matches found
}
return date;//return matching date
}
public static void main(String[] args)
{
String str = "10.223.157.186 - - [15/Jul/2009:14:58:59 -0700] "GET / HTTP/1.1" 403 202";//string

System.out.println("Ip address:"+FindIpAdress(str));//FindIpAdress method called
System.out.println("Date:"+FindDate(str));//FindDate method called
}
  
}
Output:

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