x | P (x) |
3 | 0.11 |
4 | P=? |
6 | 0.02 |
7 | 0.6 |
Find the value of P to make this a probability distribution
As per the axioms of probability distribution,
So
Hence
Answer here is P=0.27
Solve the newsvendor problem. Probability 0.11 0.11 0.19 0.22 0.11 0.26 Value 1 2 3 4 5 6 Purchase cost c = 25 Selling price p = 35 Salvage value v = 17
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Poisson Probabilities x l 3 2 7 8 4 6.3 4 6 a) P(x=3) = b) P(x=7) = c) P(x=4) = d) P(x<4) = Build the probability distribution table and graph and use to calculate the probability of x being equal or less than 4
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Week5 Saved Solve the newsvendor problem. Probability Value 0.11 0.10 2 0.31 3 0.21 4 0.11 5 0.16 6 Purchase cost e=17 Selling price p= 33 Salvage value v= 10 What is the optimal order quantity? Optimal order quantity < Prev Te to search 3 of 15 Nex
Consider the following cumulative distribution function for X. 7 0.1 08 0.9 1.0 Fo) 0.3 0.6 (i) Determine the probability distribution. ii) Find P(X < 1). iii Find P(0 <XS5).
calculate the mean and standard deviation using this discrete probability distribution: x-4.5, 6, 7, 9.5 P(x)-0.33, 0.11, 0.21, 0.35