Prepare two test tubes, one containing 5 mL water and one containing 5 mL 0.15 NaCl....
Prepare two test tubes, one containing 5 mL water and one containing 5 mL 0.15 NaCl. Add 0.5 mL of blood to each tube, mix and observe by placing a piece of paper behind each. Which one of these solution will hemolyse? (hint: Only one solution hemolyse). please explain why.
Homework Answers
RBC will undergo lysis in the presence of sodium chloride.
0.9% solution of sodium chloride is isotonic to red blood cells. When RBC is are kept in this solution, then there is no net movement of water and therefore the shape and morphology of the cells remain the same.
A solution of 0.9%, like 0.15%, which is given in the question, is hypotonic to red blood cells. Water will enter into the cell from outside resulting in swelling and ultimate breakdown of the cells.
In case the solution is greater than 0.9 %, it will become hypertonic. In this case water will be lost from the cells and they will undergo plasmolysis.
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