An object is located to the left of a convex lens whose focal length is 38 cm . The magnification produced by the lens is m1 = 3.3.
To increase the magnification to 4.5, should the object be moved closer to the lens or farther away? Farther away
can you please Calculate the distance through which the object should be moved???
An object is located to the left of a convex lens whose focal length is 38...
Constants | Periodic Table Part A IP An object is located to the left of a convex lens whose focal length is 40 cm. The magnification produced by the lens is m 28 To increase the magnification to 4.1, should the object be moved closer to the lens or farther away? closer farther away Correct Part B Explain. Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 800 Character(s) remaining Submit Request An Part C Calculate...
An object is located 15.0 cm to the left of a diverging lens whose focal points are 35.2 cm from the lens. (a) Determine the distance (unsigned) of the image from the lens. distance cm location ---Select--- to the right of the lens to the left of the lens (b) Determine the magnification of the image
You have a concave (diverging) lens with a −30 cm focal length. The magnification produced by the lens for a particular object distance is m = 1/2 and you wish to decrease the magnification to m = 1/8. Determine the distance and direction (away from or closer to the lens) through which the object must be moved in order to accomplish this.
An object is 22.0 cm to the left of a lens that has a focal length of +8.50 cm. A second lens, which has a focal length of -29.0 cm, is 5.80 cm to the right of the first lens. (a) Find the distance between the object and the final image formed by the second lens. (b) What is the overall magnification? Please help with parts A and B. Thanks! An object is 22.0 cm to the left of a...
An object is on the left side of a thin converging lens. The object is located at a distance of 6 cm away from a thin converging lens with focal length of 2 cm. Use the thin lens equation (1/f = 1/s' + 1/s) to predict the following: (a) Location of the image? (b) Magnification of the image (including inverted versus non-inverted)? (c) Real or virtual? Draw diagram please!
An object is located 20.4 cm to the left of a diverging lens having a focal length f = −31.8 cm. (a) Determine the location of the image. distance: __________ location: ___________ (b) Determine the magnification of the image. _____________
An object is 22.3 cm to the left of a lens that has a focal length of +8.5 cm. A second lens, which has a focal length of -30 cm, is 5.49 cm to the right of the first lens. An object is 22.3 cm to the left of a lens that has a focal length of +8.5 cm. A second lens, which has a focal length of -30 cm, is 5.49 cm to the right of the first lens....
An object is located 23.0 cm to the left of a diverging lens having a focal length f = −37.2 cm. (a) Determine the distance and location of the image. (b) Determine the magnification of the image. (c) Construct a ray diagram for this arrangement.
A spherical lens has a magnification is +3.0. (a) Determine the focal length in terms of the object distance. (b) Suppose the object is located 6.0 cm to the left of the mirror. What are the focal length and image distance? (c) Is the lens concave or convex? (d) Using a ray diagram, confirm the locations of the image and focal point.
An object is placed to the left of a converging lens of focal length f = 30 cm, such that the object-to-image distance is 7 cm. Find the magnification.