You have a concave (diverging) lens with a −30 cm focal length. The magnification produced by the lens for a particular object distance is m = 1/2 and you wish to decrease the magnification to m = 1/8. Determine the distance and direction (away from or closer to the lens) through which the object must be moved in order to accomplish this.
You have a concave (diverging) lens with a −30 cm focal length. The magnification produced by...
An object is located to the left of a convex lens whose focal length is 38 cm . The magnification produced by the lens is m1 = 3.3. To increase the magnification to 4.5, should the object be moved closer to the lens or farther away? Farther away can you please Calculate the distance through which the object should be moved???
A concave lens has a focal length of -36 cm. Find the image distance and magnification that results when an object is placed 19 cm in front of the lens. (Use the proper sign convention for both quantities.) When an object is located 61 cm to the left of a lens, the image is formed 25 cm to the right of the lens. What is the focal length of the lens? An object with a height of 2.22 cm is...
A concave lens refracts parallel rays in such a way that they are bent away from the axis of the lens. For this reason, a concave lens is referred to as a diverging lens. Part A Consider the following diagrams, where F represents the focal point of a concave lens. In these diagrams, the image formed by the lens is obtained using the ray tracing technique. Which diagrams are accurate?(Figure 1) (Figure 2) (Figure 3) (Figure 4) Type A if...
An object is 13.8 cm from the surface of a concave (diverging) thin lens of focal length of 8.0 cm (magnitude only). What is the image distance, in cm, BLANK-1 and magnification BLANK-2 of this arrangement? (Do not enter units with answer.)
Consider a diverging lens of focal length f--20 cm and a virtual object placed 30 cm from the lens. Find the image distance q in centimeters. You may wish to complete this ray diagram Pick 10.0, -10.0, -50.0, -60.O, Consider a diverging lens of focal length f--20 cm and a virtual object placed 30 cm from the lens. Find the image distance q in centimeters. You may wish to complete this ray diagram Pick 10.0, -10.0, -50.0, -60.O,
14. An object is 2 cm from a concave (diverging) lens. The resulting height of the virtual image is half as large as the the height of the object. What is the focal length of the lens? (Hint: Use the information given to determine the lateral magnification, and from that determine the image distance. The use the thin lens equation.) (A) - cm (B) - cm (C) -1 cm (D) –2 cm
A concave lens has a focal length of -35 cm . Find the image distance and magnification that results when an object is placed 18 cm in front of the lens. fiind di in cm and m
The focal length of a diverging lens is negative. If f = −23 cm for a particular diverging lens, where will the image be formed of an object located 32 cm to the left of the lens on the optical axis? ______cm to the left of the lens? What is the magnification of the image? b. A small object is placed to the left of a convex lens and on its optical axis. The object is 29 cm from the...
A concave lens has a focal length of -38 cm. a) Find the image distance that results when an object is placed 32 cm in front of the lens. (di = ? cm) b) Find the magnification that results when an object is placed 32 cm in front of the lens. (m=?)
1.) An object is placed in front of a diverging lens with a focal length of 17.7 cm. For each object distance, find the image distance and the magnification. Describe each image. (a) 35.4 cm location _____cm magnification _____ nature real virtual upright inverted (b) 17.7 cm location _____ cm magnification _____ nature real virtual upright inverted (c) 8.85 cm location _____ cm magnification _____ nature real virtual upright inverted 2.) An object is placed in front of a converging lens...