Question

Week 1

1 InClass Exercise: Pointer Values

Due

: Friday

March 27, 2020

(8 marks

)

Indicate what the screen output is for the following code. Show your work on how you determined the

values.

#include

<stdio.h>

void MyFunction(

char *Msg);

int main(

void )

{

char *pChar, MyString[] =

"Hello World"

;

pChar = MyString;

putchar(pChar[2]);

printf(

"\n" );

putchar(*(pChar + 5));

printf(

"\n" );

pChar = &MyString[3];

puts(pChar);

pChar = &MyString[1];

MyFunction(pChar);

MyFunction

II (pChar);

return

0;

}

// --------------------------------------------

void MyFunction(

char *Msg )

{

char *pMsg;

pMsg = &

Msg [5];

puts(pMsg);

}

// --------------------------------------------

void MyFunction(

char *Msg )

{

char *pMsg;

pMsg = &

Msg [-1];

puts(pMsg)

Answer 1

The answer to the above problem will be as follows-

The Final output on screen will be like this below-

l

<blank space>

lo World

World

Hello World

Now the code along with the explanation is as below-

The explanation is written as comments along with the code.

The image of explanation in the form of comments is below-

In the image below, it is mentioned how each line of code produces what output. The description is given in comments.

First, pChar is assigned the value "Hello World".

so when putchar(pChar[2]) is executed, it prints value at index 2 which is l

Now there is a change in line.

next character at index 5 is printed, which is a blank space. So nothing is displayed.

Again line is changed.

now string starting from index 3 is printed, which results in lo World

Then pChar is assigned value starting from index 1,i.e, "ello World" and the two functions are called on this value.

The first function prints this "ello World" from index 5, so it prints World

The second function prints the entire string because index mentioned is -1, so it displays ello World

This is the entire explanation also mentioned in comments along side the code below.

If this answer helps, please give an up vote and feel free to comment for any query.