Question

According to the following reaction, how many grams of chlorine gas are required for the complete reaction of 32.6 grams of carbon disulfide?

Answer 1

CS2 + 3Cl2 -----> CCl4 + S2Cl2

1 mole of CS2 reacts with 3 moles of Cl2 .

Molar mass of CS2 = 76.139 g/mol

Molar mass of Cl2 = 70.906 g/mol

So, 76.139 g of CS2 reacts with 3*70.906 g of Cl2

And 1g of CS2 requires 3*70.906 /76.139 g of Cl2

32.6 g requires = 3*70.906*32.6/76.139 of Cl2

Which on solving gives 91.107 g of Cl2