Question

Help c++ please

3 easy questions, that's why I put them together, not worth asking each one individually.

1) If test() were called 3 more times, what would be last line printed by test()?

2)

What is the output of the following code? (Note that there are no endl's, all output is on a single line)

int vol(int s);
int vol(int x, int y, int z=1);
int main()
{
   cout << vol(2) << "-";
   cout << vol(3, 2) << "-";
   cout << vol(3, 2, 4);
   return 0;
}
int vol(int s)
{
   return s * s * s;
}
int vol(int x, int y, int z)
{
   return x * y * z;
}

3)  

What is the output of the following code? (Note that there are no endl's, all output is on a single line)

void fun(int &a, int b, int &c);

int main()
{
   int a = 1;
   int b = 2;
   int c = 3;
   fun(a, b, c);
   cout << a << '-' << b << '-' << c << '-';
   fun(b, c, a);
   cout << a << '-' << b << '-' << c;
   return 0;
}
void fun(int &a, int b, int &c)
{
   a = a + 3;
   b = a * 4;
   c++;
}

Answer 1

Answer-

2- This program output is- 8-6-24. This program has 2 functions-first with one parameter and the second 3 parameters.

int vol(int s)

{

s*s*s;

}

This function is taking one value as one parameter and returning value is – multiply the value three times. When this function is calling value 2 is passing then it is taking and returning 8. That is the correct and after 8 it is printing ‘–‘ because there is print statement after calling function print ‘-‘ that’s why it is printing.

Next function is- int vol(int x, int y, int z=1). In this function, all three parameters are multiplying each together and returning the product.

In program. The second function is called with 2 parameters passing then it will this function. Parameters values are- 3,2. It is taking both values as x,y and z already initialized so it is multiplying all-3*2*1= 6 it is returning with dash because in printing statement dash is printing.

Next time also function is called with 3 parameters vol(3,2,4); It is taking values x,y,z now there is a value for z also so it will store in z=4 then it will multiply and return the product. 3*2*4=24

Output is- 8-6-24

3- This program has one function with 3 parameters, two’s are reference variables and one is actual parameters.

The program output is 4-2-4-5-5-4.

When a parameter is passed by value, a copy of the parameter is made. Therefore, changes made to the formal parameter by the called function have no effect on the corresponding actual parameter. Look at your program- there is a variable b is the actual parameter when we are changing in this variable there is no effect to b variable.

When a parameter is passed by reference, the conceptually actual parameter itself is passed( just given the name of the corresponding formal parameter. That’s why any changes made to the formal parameter do affect the actual parameter. In program 3 we can see reference variable changes their values.

1- I am confused about this one what you want, there is no code also. Just comment me in the comment box I'll provide your answer.