Question

In an 2D array I have the following data stored. Now I have to do code in C language to do the following:

If distance between 1 &4 and 5&8 in any line is greater than 2 , then delete that row. And then update the 2D array. If there is no pair of 1 &4 or 5&8 in any row skip that row.

Please help to do the code in C.

0 1 2 3 4 9

0 1 2 3 7 8 9

0 1 2 6 7 3 4 9

0 1 2 6 7 8 9

0 5 6 2 3 4 9

0 5 6 2 3 7 8 9

0 5 6 7 3 4 9

0 5 6 7 8 9

Result:

0 1 2 3 4 9

0 1 2 3 7 8 9

0 1 2 6 7 8 9

0 5 6 2 3 4 9

0 5 6 7 3 4 9

0 5 6 7 8 9

Answer 1

Please let me know you need more information:-

========================================

====

#include <stdio.h>

int main()
{
  
int myArray[8][8] = {
{ 0,1,2,3,4,9 },

{ 0,1,2,3,7,8,9 },

{ 0,1,2,6,7,3,4,9 },

{ 0,1,2,6,7,8,9 },

{ 0,5,6,2,3,4,9 },

{ 0,5,6,2,3,7,8,9 },

{ 0,5,6,7,3,4,9 },

{ 0,5,6,7,8,9 }

};
  
for(int i =0 ; i < 8 ;i++){
int print = 1;
for(int j=0;j<8;j++){
  
if(myArray[i][j] == 1){
//printf("%d == > j=%d \n" , myArray[i][j] ,j);
for(int k = j,t=j ; k<8-j;k++,t++){
// printf("%d == > k=%d , x=%d\n" , myArray[i][k] ,k,t);
if(myArray[i][k] == 4 && t>4){
//swap the array Do not print this.
print = 0;
break;
}
}
}
if(myArray[i][j] == 5){
//printf("%d == > j=%d \n" , myArray[i][j] ,j);
for(int k = j,x=1 ; k<8-j ;k++,x++){
//printf("%d == > k=%d , x=%d\n" , myArray[i][k] ,k,x);
if(myArray[i][k] == 8 && x>4){
//swap the array Do not print this.
print = 0;
break;
}
}
}
  
}
if(print != 0){
for(int p=0;p<(sizeof(myArray[0])/sizeof(myArray[0][0]));p++){
printf("%d ",myArray[i][p]);
}
printf("\n");
}

}
  

return 0;
}

==

====

===

OUTPUT:-

==

0 1 2 3 4 9 
0 1 2 3 7 8 9  
0 1 2 6 7 8 9  
0 5 6 2 3 4 9  
0 5 6 7 3 4 9  
0 5 6 7 8 9 

==

Please let me know you need more information:-

==

Thanks