Given the ground state electron configuration of 16S 1s2 2s2 2p6 3s23p4, the distribution of the...
Given the ground state electron configuration of 16S 1s2 2s2 2p6 3s23p4, the distribution of the electrons on the last subshell 3p can be represented by
Keep in mind the _ means an empty space in that mL
Group of answer choices
a. ↑↓ ↑↓ ↑↓
b. ↑↓ ↓_ ↑_
c. ↑↓ ↑_ ↑_
d. ↑↓ ↑↓ ↑_ __ __
e. ↑↓ ↑↓ __
Which of the following statements is FALSE ?
Group of answer choices
Like classical physics, we can simultaneously solve for the momentum and position of an electron
Electrons are found in atomic orbitals located at discrete energy levels
Electrons have both wave and light properties
Electrons fill the orbitals at the lowest energy level first
Homework Answers
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Given the ground state electron configuration of 16S
1s2 2s2 2p6
3s23p4, the
distribution of the...
Q2: b) Three elements have the electron configurations: 1s' 2s2 2p 3s 3p 1s2 2s2 2p6...
Q2: b) Three elements have the electron configurations: 1s' 2s2 2p 3s 3p 1s2 2s2 2p6 3s2 1s2 2s2 2p6 3s 3p 4s. The first ionization energies of these elements (not in the same order) are: 0.419, 0.735, 1.527 MI/mol (MJ for mega Jouls). The atomic radii are 1.60 A°, 0.98 A°, 2.35 A°. Identify the three elements and match the appropriate values of ionization energy and atomic radius to each configuration Element Atomic Radius lonization Energy 1. 2. 3.
What is the ground state electron configuration of Rubidium ( Rb ) ? a) 1s2 2s2...
What is the ground state electron configuration of Rubidium ( Rb ) ? a) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 c) 5s1 b) 1s2 2s2 2p6 3s2 3p6 4s2 4p6 4d10 5s1 d) 1s2 2s2 2p6 3s2 3p6 3d10 4p6 5s2 5p2
The electronic configuration for sodium is 1s2 2s2 2p6 3s1, and the electronic configuration for potassium...
The electronic configuration for sodium is 1s2 2s2 2p6 3s1, and the electronic configuration for potassium is 1s2 2s2 2p6 3s2 3p6 4s1. It requires 5.1 eV to remove the outermost electron (3s1) from sodium. What can you say about the energy required to remove the outermost electron from potassium (4s1)? Since each is the outermost electron around the atom, the energy required will be equal to 5.1 eV. Since each electron is in an s orbital, the energy required...
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 is the complete electron configuration for what element...
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 is the complete electron configuration for what element with a negative one charge?
The electronic configuration for boron is 1s2 2s2 2p1, and the electronic configuration for aluminum is...
The electronic configuration for boron is 1s2 2s2 2p1, and the electronic configuration for aluminum is 1s2 2s2 2p6 3s2 3p1. It requires 8.298 eV to remove the outermost electron (2p1) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Group of answer choices Since each is the outermost electron around the atom, the energy required will be equal to 8.298 eV. Since each electron is in a p orbital, the...
1. Which element has the electron configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2...
1. Which element has the electron configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d5 ? a. Br b. Mn c. Nb d. Tc 2. What is the value of 27oC on the Fahrenheit scale? Group of answer choices a. -6.8 b. 106 c. 300 d. 81 e. none of these 3. Which of the following atoms has the largest radius? Group of answer choices a. S b. Se c. Br d. O
The electronic configuration for boron is 1s2 2s2 2p1, and the electronic configuration for aluminum is...
The electronic configuration for boron is 1s2 2s2 2p1, and the electronic configuration for aluminum is 1s2 2s2 2p6 3s2 3p1. It requires 8.298 eV to remove the outermost electron (2p1) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 eV. Since each electron is in a p orbital, the energy required will be equal...
Can you please please help and show work and a small description for me to understand?...
Can
you please please help and show work and a small description for me
to understand? Thank you
7 An atom of chromium has unpaired electrons and is A) 3, diamagnetic 5, diamagnetic 3, paramagnetic 5, paramagnetic 6, paramagnetic B) C) D) E) 8 The electronic configuration and filling order of the element whose atomic number is 26 is: A) 1s2 2s2 2p6 3s2 3p6 4s0 3d8 B) 1s2 2s2 2p6 3s2 3p6 3d6 4s2 1s2 2s2 2p6 3s2 3p6...
Match the predicted ground state electron configuration with the following elements: a. oxygen b. cesium c....
Match the predicted ground state electron configuration with the following elements: a. oxygen b. cesium c. lithium e. d. phosphorus gallium f. lanthanum 6. 1s 2s 2p 3s2 3p6 4s2 3d10 4p6 582 4d10 5p6 652 44 7. 1s2 2s2 2p 3s2 3p™ 452 3dłº 4p1 8. 1s2 2s 2p4 9. 1s 2s 2p™ 352 3p™ 452 3d10 4p6 552 4d10 5p 6s! 10. 1s 2s 2p6 3s 3p3
3. In the ground electronic state of Li atom, the electron configuration is 1s 2s'. If...
3. In the ground electronic state of Li atom, the electron configuration is 1s 2s'. If we neglect all the electron-electron repulsion, and assume all Li atomic orbitals follow those in hydrogenic atoms. Determine the energy (in eV) of the electron ground state: 1s2 2s1. Namely, the total energy of the 3 electrons in 1s 2s'. Check the end of chapter problem: E8C.2(a). 3. In the ground electronic state of Li atom, the electron configuration is 1s 2s1. If we...
Q2: b) Three elements have the electron configurations: 1s' 2s2 2p 3s 3p 1s2 2s2 2p6 3s2 1s2 2s2 2p6 3s 3p 4s. The first ionization energies of these elements (not in the same order) are: 0.419, 0.735, 1.527 MI/mol (MJ for mega Jouls). The atomic radii are 1.60 A°, 0.98 A°, 2.35 A°. Identify the three elements and match the appropriate values of ionization energy and atomic radius to each configuration Element Atomic Radius lonization Energy 1. 2. 3.
Can
you please please help and show work and a small description for me
to understand? Thank you
7 An atom of chromium has unpaired electrons and is A) 3, diamagnetic 5, diamagnetic 3, paramagnetic 5, paramagnetic 6, paramagnetic B) C) D) E) 8 The electronic configuration and filling order of the element whose atomic number is 26 is: A) 1s2 2s2 2p6 3s2 3p6 4s0 3d8 B) 1s2 2s2 2p6 3s2 3p6 3d6 4s2 1s2 2s2 2p6 3s2 3p6...
Match the predicted ground state electron configuration with the following elements: a. oxygen b. cesium c. lithium e. d. phosphorus gallium f. lanthanum 6. 1s 2s 2p 3s2 3p6 4s2 3d10 4p6 582 4d10 5p6 652 44 7. 1s2 2s2 2p 3s2 3p™ 452 3dłº 4p1 8. 1s2 2s 2p4 9. 1s 2s 2p™ 352 3p™ 452 3d10 4p6 552 4d10 5p 6s! 10. 1s 2s 2p6 3s 3p3
3. In the ground electronic state of Li atom, the electron configuration is 1s 2s'. If we neglect all the electron-electron repulsion, and assume all Li atomic orbitals follow those in hydrogenic atoms. Determine the energy (in eV) of the electron ground state: 1s2 2s1. Namely, the total energy of the 3 electrons in 1s 2s'. Check the end of chapter problem: E8C.2(a). 3. In the ground electronic state of Li atom, the electron configuration is 1s 2s1. If we...
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