Question

A uniform electric field of magnitude 450 V/m is directed in the positive x-direction. A 18 µC charge moves from the origin to the point (x, y) = (20 cm, 50 cm).

(a) What was the change in the potential energy of this charge?
= J
(b) Through what potential difference did the charge move?
= V

Answer 1

PART A:

The electric field is in the +x direction.

The electric field is only in the x-direction. So, only x component is important for our question.

So, The change in potential energy is given by

PART B:

The potential difference is given by