At 20°C, the solubility of lead (II) iodide is 0.0756 g·100 mL-1. Using this data, calculate...
At 20°C, the solubility of lead (II) iodide is 0.0756 g·100 mL-1. Using this data, calculate Ksp for lead (II) iodide at 20°C.
hints-
Lead (II) iodide is a bright yellow solid. What is the formula for lead (II) iodide?
What would be the mathematical expression for Ksp for lead (II) iodide?
How would you convert solubility in grams/100 mL to grams/litre?
How would you convert grams/litre to moles/litre?
Homework Answers
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At 20°C, the solubility of lead (II) iodide is 0.0756 g·100
mL-1. Using this data, calculate...
When aqueous lead (II) nitrate is added to aqueous potassium iodide, the brilliant yellow solid, lead...
When aqueous lead (II) nitrate is added to aqueous potassium iodide, the brilliant yellow solid, lead (II) iodide forms (as well as aqueous potassium nitrate). Write out the balanced chemical equation for this precipitation reaction. According to the solubility rules provided in class, would you predict an insoluble precipitate, considering the two reactants added together? Why or why not? If 300.0 mL of a 0.10 M solution of each reactant is added together, how many grams of lead (II) iodide...
The solubility of lead (ii) iodide is 0.064 g/100 ml at 20oC. What is the solubility...
The solubility of lead (ii) iodide is 0.064 g/100 ml at 20oC. What is the solubility product for lead (ii) iodide? Please show work, thanks!
Find the solubility of Lead (II) iodide (MW = 461.2 g/mol) in g/100 mL if the...
Find the solubility of Lead (II) iodide (MW = 461.2 g/mol) in g/100 mL if the Ksp is equal to 8.30x10-9 Steps and explanation please! Thanks in advance!
How many grams of lead (II) iodide would be produced based on the amount...
How many grams of lead (II) iodide would be produced based on
the amount of lead (II) nitrate used?
What is the theoretical yield of lead (II) iodide (in grams) for
this reaction based on the limiting reactant?
What was the actual yield (in grams) of the solid for this
experiment?
What was the percent yield of the reaction?
How many moles of iodide were left unreacted?
How many moles of NaI were left unreacted?
How many grams...
4. Gram solubility can be calculated from the molar solubility by using the molar mass of...
4. Gram solubility can be calculated from the molar solubility by using the molar mass of the solid, Do You Understand? 1. Consider the equilibrium that is established when dissolving scandium fluoride (ScFz) in water. a. Write the Ksp expression (with b. Write the Ksn expression with each concentration algebraically respect to molar concentrations) expressed in relation to the molar solubility. (This is the one with for this salt. all the x's in it). chemPad Help Greek chemPad Help Greek...
The solubility of lead(II) iodide in water is 0.62 grams per 1.0 L of solution. What is the solubility product cons...
The solubility of lead(II) iodide in water is 0.62 grams per 1.0 L of solution. What is the solubility product constant, Ksp. for the dissolution? Pb/z(s) ++ Pb2+ (aq) + 2/"(aq) O 4.0x10-3 O 9.7x10-9 2.4x10-9 O 1.8x10-6
1- A saturated solution of lead(II) iodide, PbI2 has an iodide concentration of 3.0*10^-3 mol/L. a- What is the molar...
1- A saturated solution of lead(II) iodide, PbI2 has an iodide concentration of 3.0*10^-3 mol/L. a- What is the molar solubility of PbI2? b- Determine the solubility constant, Ksp for lead (II) iodide. c- Does the molar solubility of lead(II) iodide increase, decrease or remain unchanged with the addition of potassium iodide to the solution? Explain? 2- The Ksp of Ca(OH)2 was 5.2*10^-6 and 4.8*10^-6 respectively. a- What is the average Ksp of Ca(OH)2?
The solubility of lead (II) bromide (g/100 g water) at 50 °C and 100 °C is,...
The solubility of lead (II) bromide (g/100 g water) at 50 °C and 100 °C is, 1.94 g, and 4.75 g. respectively. What would be the correct terms to describe solutions of 2.5 g PbBr2 in 100 mL water at 50°C and 100 °C? none of these answers saturated and saturated, respectively saturated and unsaturated, respectively O unsaturated and unsaturated, respectively
7. The solubility of lead(111 fodide is 0.064 g/100 ml at 20°c. what is the solubility...
7. The solubility of lead(111 fodide is 0.064 g/100 ml at 20°c. what is the solubility product constant for leadili) iodide at this temperature? Answer: 8. Addition of a common ion to a solution of a slightly soluble salt the solubility of the slightly soluble salt. Answer: 9. According to the first law of thermodynamics the internal energy of an isolated system must Answer: 10. According to the first law of thermodynamics if the energy of a system decreases amount...
Experiment 22 Prelaborator Molar Solubility, Comm Date Lab Sec. _ Name 1. A saturated solution of lead(II) iodide,...
Experiment 22 Prelaborator Molar Solubility, Comm Date Lab Sec. _ Name 1. A saturated solution of lead(II) iodide, Pbl, has an iodide concentration of 3.0 X 10 mol/L (see photo). a. What is the molar solubility of Pl_.? b. Determine the solubility constant, Ko, for lead(II) iodide. c. Does the molar solubility of lead(II) iodide increase, decrease, or remain unchanged with the addition of potassium iodide to the solution? Explain.
How many grams of lead (II) iodide would be produced based on
the amount of lead (II) nitrate used?
What is the theoretical yield of lead (II) iodide (in grams) for
this reaction based on the limiting reactant?
What was the actual yield (in grams) of the solid for this
experiment?
What was the percent yield of the reaction?
How many moles of iodide were left unreacted?
How many moles of NaI were left unreacted?
How many grams...
4. Gram solubility can be calculated from the molar solubility by using the molar mass of the solid, Do You Understand? 1. Consider the equilibrium that is established when dissolving scandium fluoride (ScFz) in water. a. Write the Ksp expression (with b. Write the Ksn expression with each concentration algebraically respect to molar concentrations) expressed in relation to the molar solubility. (This is the one with for this salt. all the x's in it). chemPad Help Greek chemPad Help Greek...
The solubility of lead(II) iodide in water is 0.62 grams per 1.0 L of solution. What is the solubility product constant, Ksp. for the dissolution? Pb/z(s) ++ Pb2+ (aq) + 2/"(aq) O 4.0x10-3 O 9.7x10-9 2.4x10-9 O 1.8x10-6
The solubility of lead (II) bromide (g/100 g water) at 50 °C and 100 °C is, 1.94 g, and 4.75 g. respectively. What would be the correct terms to describe solutions of 2.5 g PbBr2 in 100 mL water at 50°C and 100 °C? none of these answers saturated and saturated, respectively saturated and unsaturated, respectively O unsaturated and unsaturated, respectively
7. The solubility of lead(111 fodide is 0.064 g/100 ml at 20°c. what is the solubility product constant for leadili) iodide at this temperature? Answer: 8. Addition of a common ion to a solution of a slightly soluble salt the solubility of the slightly soluble salt. Answer: 9. According to the first law of thermodynamics the internal energy of an isolated system must Answer: 10. According to the first law of thermodynamics if the energy of a system decreases amount...
Experiment 22 Prelaborator Molar Solubility, Comm Date Lab Sec. _ Name 1. A saturated solution of lead(II) iodide, Pbl, has an iodide concentration of 3.0 X 10 mol/L (see photo). a. What is the molar solubility of Pl_.? b. Determine the solubility constant, Ko, for lead(II) iodide. c. Does the molar solubility of lead(II) iodide increase, decrease, or remain unchanged with the addition of potassium iodide to the solution? Explain.
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