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7. The solubility of lead(111 fodide is 0.064 g/100 ml at 20°c. what is the solubility product constant for leadili) iodide a

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These questions are answered by using simple concept of thermodynamics of first law of thermodynamics and entropy.

The answer is given in the image,

Answer: 7 Pb 1a = 207+2x127 = 461 g/mol Solubility = 0.064g/100ml = 0064 X1000 M 461 X 100 S=1.4×10-3M Pblues = pod + 21- Ksp

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