Find the solubility of Lead (II) iodide (MW = 461.2 g/mol) in g/100 mL if the Ksp is equal to 8.30x10-9
Steps and explanation please! Thanks in advance!
Find the solubility of Lead (II) iodide (MW = 461.2 g/mol) in g/100 mL if the...
The solubility of lead (ii) iodide is 0.064 g/100 ml at 20oC. What is the solubility product for lead (ii) iodide? Please show work, thanks!
At 20°C, the solubility of lead (II) iodide is 0.0756 g·100 mL-1. Using this data, calculate Ksp for lead (II) iodide at 20°C. hints- Lead (II) iodide is a bright yellow solid. What is the formula for lead (II) iodide? What would be the mathematical expression for Ksp for lead (II) iodide? How would you convert solubility in grams/100 mL to grams/litre? How would you convert grams/litre to moles/litre?
1- A saturated solution of lead(II) iodide, PbI2 has an iodide concentration of 3.0*10^-3 mol/L. a- What is the molar solubility of PbI2? b- Determine the solubility constant, Ksp for lead (II) iodide. c- Does the molar solubility of lead(II) iodide increase, decrease or remain unchanged with the addition of potassium iodide to the solution? Explain? 2- The Ksp of Ca(OH)2 was 5.2*10^-6 and 4.8*10^-6 respectively. a- What is the average Ksp of Ca(OH)2?
If 800 mg of lead(11) iodide (MM 461 g/mol) are placed in 1000 mL of pure water, how many milligrams of lead (II) iodide dissolve? Ksp= 4.4x10-9 All 800 mg of lead(II) iodide dissolve Less than 450 mg do not dissolve, but some lead(11) iodide does O All 800 mg of lead(tl) iodide do not dissolve O 450 mg amount do not dissolve Less than 800 mg but more than 450 mg do not dissolve
A saturated solution of lead (II) iodide, PbI2 has an iodide concentration of 3.0 × 10-3 mol/ L. Calculate the solubility constant, Ksp, for lead (II) iodide. PbI2 (s) ß---à Pb2+(aq) + 2I-(aq) A saturated solution of lead (II) iodide, Pbl2 has an iodide concentration of 3.0 x 10-3 mol/ L. Calculate the solubility constant, Ksp, for lead (II) iodide Pbl2 (s) 8 3.5 x 10-8 5.0 x 10-8 2.8 x 10-8 1.4 x 10-8 -à Pb2 (aq)+2I(aq)
A saturated solution of lead(II) iodide, PbI2 has an iodide concentration of 3.0 x 10^-3 mol/L. a) What is the molar solubility of PbI2? b) Determine the solubility constant, Ksp, for lead(II) iodide. c) Does the molar solubility of lead (II) iodide increase, decrease, or remain unchanged with the addition of potassium iodide to the solution? EXPLAIN.
Lead(II) sulfate is the crust that forms on battery terminals, its solubility in water is 0.00425 g/ 100 mL. If 20.0 kg of lead(II) sulfate has been stored of in a 100 L tank filled with water what is the concentration of Pb2+ in the water? (KSP = 6.3 x 10-7, MW = 303.26 g/mol)
6 What is the solubility of lead(II)iodide in a 0.50M solution of KI? (Ksp for Pbl = 7.9x109) DO NOT ENTER UNITS. 1 Nitrogen and hydrogen gases react to produce ammonia gas: N.(g) + 3H2(g) -> 2NH3(g) What is K, for this reaction? AG°=-32.7 kJ/mol
Determine the molar solubility of lead (II) iodide, PbI2, in 0.0500 mol/L NaI.
The Ksp for lead iodide (PI) is 1.4 x 10-8. Calculate the solubility of lead iodide in each of the following. a. water Solubility = mol/L b. 0.18 M Pb(NO3)2 Solubility = mol/L c. 0.018 M Nal Numeric input field Solubility = mol/L