Answer:-
The first question is solved by using the simple concept of dissolution of salt in common ion solution and the second question is solved by using the simple formula of Kp and Gibbs free energy.
The answer is given in the image,
6 What is the solubility of lead(II)iodide in a 0.50M solution of KI? (Ksp for Pbl...
For the chemical reaction 2 KI Pb(NO3)2 Pbl, + 2 KNΟ, how many moles of lead(II) iodide (Pbl2) are produced from 6.0 mol of potassium iodide (KI)? mol
What is the solubility of Pbly in a solution of 0.0046 M KI? (Ksp=7.9x10° for Pbl) O 3.73x10^-5 O 3.73x10^-6 0 2.68x10^5 O 2.89
Calculate the solubility of lead (II) iodate, Pb(IO3)2 in pure water and in a 0.50M solution of sodium iodate. The Ksp= 2.6x10^-13. Calculate the solubility of lead(II) iodate, Pb(103)2 in pure water and in a 0.50M solution of sodium iodate. The Ksp = 2.6 10-13.
Experiment 22 Prelaborator Molar Solubility, Comm Date Lab Sec. _ Name 1. A saturated solution of lead(II) iodide, Pbl, has an iodide concentration of 3.0 X 10 mol/L (see photo). a. What is the molar solubility of Pl_.? b. Determine the solubility constant, Ko, for lead(II) iodide. c. Does the molar solubility of lead(II) iodide increase, decrease, or remain unchanged with the addition of potassium iodide to the solution? Explain.
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO )2 (aq) + 2NH, l(aq) — Pbl (8) + 2NH, NO, (aq) What volume of a 0.690 M NH I solution is required to react with 883 mL of a 0.120 M Pb(NO), solution? volume: 2538.63 How many moles of Pbly are formed from this reaction? moles: 0.60927 mol Pbl:
1- A saturated solution of lead(II) iodide, PbI2 has an iodide concentration of 3.0*10^-3 mol/L. a- What is the molar solubility of PbI2? b- Determine the solubility constant, Ksp for lead (II) iodide. c- Does the molar solubility of lead(II) iodide increase, decrease or remain unchanged with the addition of potassium iodide to the solution? Explain? 2- The Ksp of Ca(OH)2 was 5.2*10^-6 and 4.8*10^-6 respectively. a- What is the average Ksp of Ca(OH)2?
Question 26 of 26 Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pbl, (s)+2NH, NO, (aq) Pb(NO) (aq) +2 NH,1(aq)- What volume of a 0.650 M NH4I solution is required to react with 587 mL. ofa 0.540 M Pb(NO3)2 solution? volume: 669.6 ml. How many moles of Pbl2 are formed from this reaction? mol Pbl moles: 0.31698 erms of use contact us help about ua pracy policy careen MacBook Pro Q...
A saturated solution of lead(II) iodide, PbI2 has an iodide concentration of 3.0 x 10^-3 mol/L. a) What is the molar solubility of PbI2? b) Determine the solubility constant, Ksp, for lead(II) iodide. c) Does the molar solubility of lead (II) iodide increase, decrease, or remain unchanged with the addition of potassium iodide to the solution? EXPLAIN.
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3), (aq) + 2NH I(aq) PbI,() +2 NH NO, (aq) What volume of a 0.150 M NH I solution is required to react with 409 mL of a 0.100 M Pb(NO3), solution? volume: How many moles of Pbly are formed from this reaction? moles: mol Pbl,
1.) Calculate the solubility of lead(II) iodate, Pb(IO3)2 in pure water and in a 0.50M solution of sodium iodate. The Ksp = 2.6 × 10‑13.