Balance the following reaction using the lowest possible whole number coefficients, in acidic conditions. (Enter coefficients...
Balance the following reaction using the lowest possible whole
number coefficients, in acidic
conditions.
(Enter coefficients for one and zero- blanks will be marked
incorrect.)
HBrO(aq) + HAsO2(aq)
+ H+(aq) + H2O(l)
+ OH−(aq) → Br−(aq) +
H3AsO4(aq) + H+(aq)
+ H2O(l) + OH−(aq)
Homework Answers
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Balance the following reaction using the lowest possible whole
number coefficients, in acidic
conditions.
(Enter coefficients...
Balance the following half reactions using the lowest possible whole number coefficients, in basic conditions. (Enter...
Balance the following half reactions using the lowest possible whole number coefficients, in basic conditions. (Enter coefficients for one and zero- blanks will be marked incorrect.) 1. Br−(aq) + H2O(l) + OH−(aq) + e− ⇌ BrO3−(aq) + H2O(l) + OH−(l) + e− Tries 0/5 2. AgO(s) + H2O(l) + OH−(aq) + e− ⇌ Ag2O3(s) + H2O(l) + OH−(l) + e− Tries 0/5
Balance the following redox reactions by balancing the half reactions and then combine the half reactions...
Balance the following redox reactions by balancing the half reactions and then combine the half reactions to get the overall balanced redox reaction with the lowest possible whole number coefficients. 1. Consider the following unbalanced redox reaction: MnO2(s) + BrO3−(aq) → MnO4−(aq) + Br−(aq) (a) Balance the corresponding half reactions in acidic conditions using the lowest possible whole number coefficients. (Enter coefficients for one and zero. Blanks will be marked incorrect.) MnO2(s) + H2O(l) + OH−(aq) + H+(aq) + e− → MnO4−(aq) + H2O(l) + OH−(aq) + H+(aq)...
2. Consider the following unbalanced redox reaction: CIO2 (aq) Cr(OH)1(s)CI(aq) +Cr04(aq) (a) Balance the corresponding half...
2. Consider the following unbalanced redox reaction: CIO2 (aq) Cr(OH)1(s)CI(aq) +Cr04(aq) (a) Balance the corresponding half reactions in acidic conditions using the lowest possible whole number coefficients Enter coeffcients for one and zero. Blanks i be marked incorrect.) CIO2 (aq) + Submil Answer Tries 0/3 H20(I) + OH (aq) + Submi AnserTries 0/3 (b) Using the results from part (a), balance the full reaction in acidic conditions with the lowest possible whole number coefficients. (Enter coefficients for one and zero....
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) NO3-...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) NO3- (aq) + As2O3(s) = N2O3(aq) + H3ASO4(aq) N03* + As2O3 + H+ + O H20=O N203+ H3A504 + H+ + H20 (b) Clozaq) + As(s) Æ HClO(aq) + H3AsO3(aq) DC103+ As + OH+ + H2O=OHCO + H2A503 + H+ + OH20 (c) CIO-(aq) + Pb(OH)42-(aq) = Cl(aq) + PbO2(s) D clo + Pb(OH)42- + D OH + H2O=D C + PbO2 + OH +...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) Balance the...
Balance the following
equations. (Use the lowest possible whole-number coefficients.
These may be zero.)
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Cr2022(aq) + I (aq) = Cr3+ (aq) + 103 (aq) 1 Cr2O72- + 1 1 + 8 H+ + 1 X H20 = 2 Cr3+ + 1 103 + 1 X H+ + 4 H2O (b) CIO3-aq) + As(s) Æ HCIO(aq) + H3A5O3(aq) 3 CIO3 + 4 As + 3 H...
Balance the following redox reaction under acidic aqueous conditions using the smallest whole- number coefficients possible....
Balance the following redox reaction under acidic aqueous conditions using the smallest whole- number coefficients possible. Cro?- (aq) + C12(aq) → 1-(aq) + Cr3+(aq)
Balance the following redox reaction under acidic aqueous conditions using the smallest whole- number coefficients possible....
Balance the following redox reaction under acidic aqueous conditions using the smallest whole- number coefficients possible. Cro,- (aq) + Cl2(aq) → OC1-(aq) + Cr3(aq)
1. (3 points) Balance the following redox reaction under acidic aqueous conditions using the smallest whole-number...
1. (3 points) Balance the following redox reaction under acidic aqueous conditions using the smallest whole-number coefficients possible. Mnog(aq) + HSQ (aq) → Mn(aq) + SO (aq) 2. (3 Points) Balance the following redox reaction under acidic aqueous conditions using the smallest whole-number coefficients possible. Croc-(aq) + C12(aq) → OC1-(aq) + Craq)
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) MnO4-(aq)...
Balance the following equations. (Use the lowest possible
whole-number coefficients. These may be zero.)
(a) MnO4-(aq) + Cl-(aq) Mn2+(aq) + Cl2(aq)
MnO4- + Cl-
+ H+ + H2O Mn2+
+ Cl2 + H+
+ H2O
(b) Cr2O72-(aq) +
NO2-(aq) Cr3+(aq) +
NO3-(aq)
Cr2O72-
+ NO2- + H+
+ H2O Cr3+
+ NO3- + H+
+ H2O
(c) Tl2O3(s) + NH2OH(aq) TlOH(s) + N2(g)
Tl2O3 + NH2OH
+ OH- + H2O TlOH(s) + N2
+ OH- + H2O
(d) CrO42-(aq) +
C2O42-(aq) Cr(OH)3(s) +
CO2(g)
CrO42-
+ C2O42-
+ OH- + H2O Cr(OH)3
+ CO2 + OH-
+ H2O
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Cr202-(aq)...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Cr202-(aq) + NO2 (aq) = Cr3+ (aq) + NO3"(aq) Cr20,2- + NO3 + H+ + H2O= Cr3+ + NO3 + H+ + H20 (b) Mn04 (aq) + CH3OH(aq) Æ Mn2+ (aq) + HCO2H(aq) MnO4 + CH3OH + H+ + H2O= Mn2+ + HCO2H + H+ + H2O (c) ClO2(aq) + H2O2(aq) = C102 (aq) + O2(9) C102 + H2O2 + OH + H20 = ClO2...
2. Consider the following unbalanced redox reaction: CIO2 (aq) Cr(OH)1(s)CI(aq) +Cr04(aq) (a) Balance the corresponding half reactions in acidic conditions using the lowest possible whole number coefficients Enter coeffcients for one and zero. Blanks i be marked incorrect.) CIO2 (aq) + Submil Answer Tries 0/3 H20(I) + OH (aq) + Submi AnserTries 0/3 (b) Using the results from part (a), balance the full reaction in acidic conditions with the lowest possible whole number coefficients. (Enter coefficients for one and zero....
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) NO3- (aq) + As2O3(s) = N2O3(aq) + H3ASO4(aq) N03* + As2O3 + H+ + O H20=O N203+ H3A504 + H+ + H20 (b) Clozaq) + As(s) Æ HClO(aq) + H3AsO3(aq) DC103+ As + OH+ + H2O=OHCO + H2A503 + H+ + OH20 (c) CIO-(aq) + Pb(OH)42-(aq) = Cl(aq) + PbO2(s) D clo + Pb(OH)42- + D OH + H2O=D C + PbO2 + OH +...
Balance the following
equations. (Use the lowest possible whole-number coefficients.
These may be zero.)
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Cr2022(aq) + I (aq) = Cr3+ (aq) + 103 (aq) 1 Cr2O72- + 1 1 + 8 H+ + 1 X H20 = 2 Cr3+ + 1 103 + 1 X H+ + 4 H2O (b) CIO3-aq) + As(s) Æ HCIO(aq) + H3A5O3(aq) 3 CIO3 + 4 As + 3 H...
Balance the following redox reaction under acidic aqueous conditions using the smallest whole- number coefficients possible. Cro?- (aq) + C12(aq) → 1-(aq) + Cr3+(aq)
Balance the following redox reaction under acidic aqueous conditions using the smallest whole- number coefficients possible. Cro,- (aq) + Cl2(aq) → OC1-(aq) + Cr3(aq)
1. (3 points) Balance the following redox reaction under acidic aqueous conditions using the smallest whole-number coefficients possible. Mnog(aq) + HSQ (aq) → Mn(aq) + SO (aq) 2. (3 Points) Balance the following redox reaction under acidic aqueous conditions using the smallest whole-number coefficients possible. Croc-(aq) + C12(aq) → OC1-(aq) + Craq)
Balance the following equations. (Use the lowest possible
whole-number coefficients. These may be zero.)
(a) MnO4-(aq) + Cl-(aq) Mn2+(aq) + Cl2(aq)
MnO4- + Cl-
+ H+ + H2O Mn2+
+ Cl2 + H+
+ H2O
(b) Cr2O72-(aq) +
NO2-(aq) Cr3+(aq) +
NO3-(aq)
Cr2O72-
+ NO2- + H+
+ H2O Cr3+
+ NO3- + H+
+ H2O
(c) Tl2O3(s) + NH2OH(aq) TlOH(s) + N2(g)
Tl2O3 + NH2OH
+ OH- + H2O TlOH(s) + N2
+ OH- + H2O
(d) CrO42-(aq) +
C2O42-(aq) Cr(OH)3(s) +
CO2(g)
CrO42-
+ C2O42-
+ OH- + H2O Cr(OH)3
+ CO2 + OH-
+ H2O
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Cr202-(aq) + NO2 (aq) = Cr3+ (aq) + NO3"(aq) Cr20,2- + NO3 + H+ + H2O= Cr3+ + NO3 + H+ + H20 (b) Mn04 (aq) + CH3OH(aq) Æ Mn2+ (aq) + HCO2H(aq) MnO4 + CH3OH + H+ + H2O= Mn2+ + HCO2H + H+ + H2O (c) ClO2(aq) + H2O2(aq) = C102 (aq) + O2(9) C102 + H2O2 + OH + H20 = ClO2...
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