What is the value of the equilibrium constant at 25 °C for a reaction that has a standard free-energy change, ΔG°, equal to 180 kJ?
T= 25.0 oC
= (25.0+273) K
= 298 K
ΔGo = 180 KJ/mol
ΔGo = 180000 J/mol
use:
ΔGo = -R*T*ln Kc
180000 = - 8.314*298.0* ln(Kc)
ln Kc = -72.6518
Kc = 2.804*10^-32
Answer: 2.80*10^-32
What is the value of the equilibrium constant at 25 °C for a reaction that has...
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