Assume that the random variable X is normally distributed, with mean mu equals 53μ=53 and standard deviation sigma equals 10σ=10. Compute the probability. Upper P left parenthesis Upper X less than or equals 40 right parenthesis(X≤40)equals=
Solution :
Given that ,
mean = = 53
standard deviation = = 10
P(x 40)
= P[(x - ) / (40 - 53) / 10]
= P(z -1.3)
Using z table,
=0.0968
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