[2pt] A spy satellite is in circular orbit around Earth. It makes one revolution in 5.99 hours. How high above Earth’s surface is the satellite?
[2pt] A spy satellite is in circular orbit around Earth. It makes one revolution in 5.99...
A spy satellite is in circular orbit around Earth. It makes one revolution in 6.02 hours. How high above Earth's surface is the satellite? What is the satellite's acceleration?
Required information A spy satellite is in circular orbit around Earth. It makes one revolution in 8.30 h. Mass of Earth is 5.974 1044 kg. radius of x Earth is 6371 km and Gravitational constant G is 6.674 10-11 N-m2/kg x How high above Earth's surface is the satellite? km
6. [2pt] A satellite is in a circular orbit around the Earth. The period of the satellite is 26.7 hr. Calculate the radius of the satellite's orbit. Data: ME=5.98 x 1024 kg, G = 6.67 x 10-11 Nm²/kg2. Answer: Submit Al Answers 7. [2pt] What is the speed of the satellite in the previous problem? Answer: (Submit All Answers)
Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 502 km above the earth’s surface, while that for satellite B is at a height of 747 km. Find the orbital speed for (a) satellite A and (b) satellite B.
Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 460 km above the earth’s surface, while that for satellite B is at a height of 774 km. Find the orbital speed for (a) satellite A and (b) satellite B.
6. [2pt] A satellite is in a circular orbit around the Earth. The period of the satellite is 20.9 hr. Calculate the radius of the satellite's orbit. Data: My = 5.98 x 10kg, -6.67 x 10 Nm²/kg? Answer: Not yet correct, tries 1/20 S t Al Answers Last Answer: 4.8x10^21 m Hint: Uniform circular motion means that the satellite is accelerated towards the center. The acceleration can be obtained from the law of gravity and the second law combined.
A top secret spy satellite is designed to orbit the Earth twice each day (i.e., twice as fast as the Earth’s rotation). What is the height of this orbit above the Earth’s surface?
4. A 1000-kg satellite in circular orbit around the Earth is moving at a speed of 7 x 10 m/s. How much work must be done to "raise" the satellite to a higher circular orbit doubling its height above the surface of the Earth?
A satellite of mass m (where m ≪ Me) is initially in a circular orbit around the Earth at a height of 410 km above the Earth’s equator. Its operators would like to move it into a geosynchronous orbit using a Hohmann transfer orbit. Assume a spherical Earth with radius 6371 km. (a) Sketch the satellite’s Hohmann transfer orbit. (b) Find the satellite’s initial (circular) orbital speed according to an inertial observer. (c) Find the maximum height of the satellite...
10-3. A 639-kg satellite is in a circular orbit about Earth at a height h = 1.16 x 10^7 m above the Earth’s surface. Find (a) the gravitational force (N) acting on the satellite, (b) the satellite’s speed (m/s) (magnitude of its velocity, not its angular velocity), and (c) the period (h) of its revolution. Caution: The radius of the satellite’s orbit is not just its height above the Earth’s surface. It also includes the radius of the Earth. The...