A certain insect has lengths that are normally distributed. The insect has a mean length of 32.4 mm and a standard deviation of 2.5mm. What percent of these insects have a length over 34mm?
Given,
= 32.4, = 2.5
We convert this to standard normal as
P( X < x) = P (Z < x - / )
So,
P( X > 34) = P( Z > 34 - 32.4 / 2.5)
= P( Z > 0.64)
= 0.2611
= 26.11%
A certain insect has lengths that are normally distributed. The insect has a mean length of...
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