A cannonball is fired from 15 m above the ground, with a speed of 40. m/s...

Question

Question

A cannonball is fired from 15 m above the ground, with a speed of 40. m/s at an angle of 35.0◦ .

(a) How long is the person in the air before hitting the ground?

(b) What is their maxiumum height?

(c) What was their total range? (Range refers to their final horizontal displacement)

Answer 1

Answer #1

The time to reach the maximum height is

where theta is the launch angle.

The maximum height reached is

The time taken to fall from this height is

the total time in air is

The range of the projectile is

given v = 40 m/s, theta = 35 degrees, H = 15 m and g = 9.8 m/s^2

Plug these values in the above equations to obtain:

a) Time in air is

b) Maximum height above ground is

c) Range is

Answer 2

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