If we have lipid standards like Phosphatidylinositol (PI), Phosphatidylethanolamine (PE), Cardiolipin (CL), Cholesterol (CH), Fatty acids (FA), Phosphatidylcholine (PC) and have been developed using a Basic solvent system (chloroform: methanol: ammonia 65:35:5) and an Acidic solvent system of (chloroform: acetone: methanol: acetic acid: water 10:4: 2: 2: 1) in a 2D-TLC plate, why would the basic solvent system have the higher Rf values for each lipid, when compared to the acidic solvent Rf?
The difference in Rf value is due to polarity of the lipid. The higher the polarity of the lipid, the less it will travel on the plate which means a low Rf value for that lipid. For example, in the basic solvent system the solvent makes a dipole in the molecule by removing a hydrogen which leads to negative charge on the molecule, this is called a polar molecule. When a molecule is polar, it binds more to the silica gel in the stationary phase and less in the mobile phase; travelling slow on the plate. The standard lipids in order of increasing (lowest to highest) polarity in basic and acidic condition are as follow: Basic CH, CL, FA, PE, PC, PI Acidic CH, FA, CL, PE, PC, PI.
If we have lipid standards like Phosphatidylinositol (PI), Phosphatidylethanolamine (PE), Cardiolipin (CL), Cholesterol (CH), Fatty acids...
From your results, rank the standard lipids by increasing order of polarity for each of the two chromatographic conditions that were assessed. Include the chemical structures of all lipids standards and, for each one, identify the polar groups. For each pair of standards, compare the polarity ranking within members of the pair. Explain your reasoning. Pair 1: FA (fatty acid) & PC (phosphatidylcholine) Pair 2: PI (phosphatidylinositol) & PE (phosphatidylethanolamine) Pair 3: CL (cardiolipin) & CH (cholesterol) CS / CHO O...