Construct the confidence interval for the population variance for the given values. Round your answers to one decimal place. n=27, s^2 =10.5 and c=0.9
Answer:
C= 90% = 0.90, =0.1
n=27, df =n-1 = 27-1 = 26
formula for confidence interval is
now calculate both critical values with df = 26
using X2 table we get critical value as
X20..05=38.8851
X20. 95 =15.3792
= (7.0207 < < 17.7513)
Therefore, based on the data provided, the 90% confidence interval
for the population variance is= 7.0< <17.8
confidence interval is = ( 7.0 , 17.8 )
Construct the confidence interval for the population variance for the given values. Round your answers to...
Construct the confidence interval for the population variance for the given values. Round your answers to one decimal place. n=14, s2=13.1, and c=0.8
Construct the confidence interval for the population variance for the given values. Round your answers to one decimal place. n=25, s2=38.3, and c=0.95
Construct the confidence interval for the population standard deviation for the given values. Round your answers to one decimal place. n=23, s=9.9, and c=0.95 Could someone help teach me the formula to solve this in Excel! Thanks so much!
Determine the critical values for the confidence interval for the population variance from the given values. Round your answers to three decimal places. n=11 and α=0.1.
Determine the critical values for the confidence interval for the population variance from the given values. Round your answers to three decimal places. n = 13 and α = 0.05 Answer: blank and blank
Use technology to construct the confidence intervals for the population variance o? and the population standard deviations. Assume the sample is taken from a normally distributed population C+0.95, 82 = 7.29, n = 27 The confidence interval for the population variance is (Round to two decimal places as needed.) The confidence interval for the population standard deviation is (Round to two decimal places as needed.)
Find the critical values x?and XR for the given confidence level c and sample size n. C=0.8, n=30 xL= (Round to three decimal places as needed.) Find the critical values x and x for the given confidence level c and sample size n. c=0.9, n=21 x?L= (Round to three decimal places as needed.) Use technology to construct the confidence intervals for the population variance o2 and the population standard deviation o. Assume the sample is taken from a normally distributed...
In order to construct a confidence interval for the population variance, a random sample of n observations is drawn from a normal population. Use this information to find χ2a/2, df and χ21 L 2, df under the following scenarios. (Round your answers to 3 decimal places. You may find it useful to reference the appropriate table: chi-square table or Ftable) a/2,d.f X"1-a/2,df a. A 90% confidence level with n- 17. b. A 90% confidence level with n- 28. C. A...
In order to construct a confidence interval for the population variance, a random sample of n observations is drawn from a normal population. Use this information to find χ2α/2,df and χ21-α/2,df under the following scenarios. (Round your answers to 3 decimal places. You may find it useful to reference the appropriate table: chi-square table or F table) χ2α/2,df χ21-α/2,df a. A 90% confidence level with n = 25. b. A 90% confidence level with n = 35. c. A 99%...
Construct a confidence interval of the population proportion at the given level of confidence. x- 120, n 1200, 99% confidence The lower bound of the confidence interval is (Round to three decimal places as needed.) The upper bound of the confidence interval is (Round to three decimal places as needed.) Construct a 99% confidence interval of the population proportion using the given information. X 105, n 150 The lower bound is The upper bound is (Round to three decimal places...