Question

In a local Japanese restaurant, we found that 35% of all customers order hot meals and that 50% of all customers are members of the American Military Community (AMC).

So let      P(H) = probability that a customer orders a hot meal = .35

                P(C) =P(complement of H) = probability that a customer chooses a cold meal = ?

                P(M) = probability that a customer is a member of the AMC = .50

                P(O)=P(complement of M) = probability that a customer is not a member of the AMC =?

                Assume we know that P(M/H) = .357                               

Note: to help you visualize this, see the Table below, reproduced in the Excel answer sheet.

	H = hot meal	C = cold meal	Sum
M = AMC			.50 = P(M)
O = not AMC			?
Sum	.35 = P(H)	?	1.0

1.            What is the probability that a randomly chosen customer is both a member of the AMC and orders a hot meal, i.e., P(H and M)? (Round to 3 digits.)

                Hint:     Remember, P(H and M) = P(H) * P (M/H)

                               

Note: Enter this number in both the answer space provided in the workseet and in the appropriate cell in the table reproduced in the worksheet.

2.           Now fill in the rest of the cells in the Table reproduced in the Excel answer sheet. (Round to 3 digits.)

3.           What is the probability that a randomly chosen customer is not a member of the AMC and does not order a hot meal, i.e., P(O and C)?   (Answer in the answer cell for question     in the Excel answer sheet. (Round to 3 digits.)

4.           What is the probability that a randomly chosen customer who is not from the AMC will choose a cold meal, i.e., find P(C/O). (Round to 3 digits.)        

5.           What is the probability that a customer either orders a cold meal or is not a member of AMC, i.e., find P(C or O)? (Round to 3 digits.)

Answer 1

	H	C	Total
M	0.125	0.375	0.5
O	0.225	0.275	0.5
sum	0.35	0.65	1

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