Question

The mean waiting time at the​ drive-through of a​ fast-food restaurant from the time an order is placed to the time the order is received is 86.286.2 seconds. A manager devises a new​ drive-through system that hehe believes will decrease wait time. As a​ test, hehe initiates the new system at hishis restaurant and measures the wait time for 1010 randomly selected orders. The wait times are provided in the table to the right. Complete parts​ (a) and​ (b) below.	108.1108.1	79.679.6	Open in StatCrunch + Copy to Clipboard + Open in Excel +
	69.269.2	94.194.1
	56.656.6	84.684.6
	73.473.4	70.870.8
	64.664.6	79.079.0

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Click the icon to view the table of correlation coefficient critical values.​(a) Because the sample size is​ small, the manager must verify that the wait time is normally distributed and the sample does not contain any outliers. The normal probability plot is shown below and the sample correlation coefficient is known to be

requals=0.9770.977.

Are the conditions for testing the hypothesis​ satisfied?

▼ Yes, No, the conditions ▼ are are not satisfied. The normal probability plot ▼ is not is linear​ enough, since the correlation coefficient is ▼ greater less than the critical value.

607590105-2-1012Time (sec)Expected z-score Edit Coordinates(0,0) A normal probability plot has a horizontal axis labeled Time (seconds) from 50 to 115 in increments of 5 and a vertical axis labeled Expected z-score from negative 2 to 2 in increments of 0.5. Ten plotted points closely follow the pattern of a line that rises from left to right through (56.5, negative 1.55) and (94, 1). All coordinates are approximate.

​(b) Is the new system​ effective? Conduct a hypothesis test using the​ P-value approach and a level of significance of

alpha equals 0.01α=0.01.

First determine the appropriate hypotheses.

Upper H 0H0​:

▼

muμ

pp

sigmaσ

▼

equals=

less than<

greater than>

not equals≠

86.286.2

Upper H 1H1​:

▼

sigmaσ

muμ

pp

▼

less than<

equals=

greater than>

not equals≠

86.286.2

Find the test statistic.

t 0t0equals=nothing

​(Round to two decimal places as​ needed.)

Find the​ P-value.

The​ P-value is

nothing .

​(Round to three decimal places as​ needed.)

Use the

alpha equals 0.01α=0.01

level of significance. What can be concluded from the hypothesis​ test?

A.

The​ P-value is

greatergreater

than the level of significance so there

isnbsp sufficient

evidence to conclude the new system is effective.

B.

The​ P-value is

greatergreater

than the level of significance so there

isnbsp not nbsp not sufficient

evidence to conclude the new system is effective.

C.

The​ P-value is

lessless

than the level of significance so there

isnbsp sufficient

evidence to conclude the new system is effective.

D.

The​ P-value is

lessless

than the level of significance so there

isnbsp not nbsp not sufficient

evidence to conclude the new system is effective.

Answer 1

Soluion Lhon- (a) yes, 78 ro io Moan 18 Cy |Σ(n-5) standard deration T2 2000, 3 -222,2S6 3E SEニーー14.9) 18-86.2 4.114 一1.739 By using P-Valu쇼 Gletdatovue not sufficienk evidence o conclude ℡ neo serum s ef&ctive CLRCFIve