AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq) What mass of silver chloride can be produced from 1.81 L of a 0.150 M...
AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq)
What mass of silver chloride can be produced from 1.81 L of a 0.150 M solution of silver nitrate?
Homework Answers
summary : first we calculate
mole of silver nitrate in solution using following equation
Mole = molarity × Volume
Then we calculate mole produced of silver chloride from given mole of silver nitrate using stoichiometric relationship.
After getting mole produce , then we multiply by molar mass of silver chloride. So we got produce mass of silver chloride.
Remember : this is true only if NaCl in excess.
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AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq)
What mass of silver chloride can be produced from 1.81 L of a
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