A researcher determines that students study an average of 8020 (MSD) minutes per week. Assuming these data are normally distributed, what is the z score for students studying 60 minutes per week? Show your work on the paper provided.
Solution :
Given that ,
mean = = 80
standard deviation = = 20
x = 60
z = (x - ) / = (60 - 80) / 20 = -20 / 20 = -1
z score = -1
A researcher determines that students study an average of 8020 (MSD) minutes per week. Assuming these...
A researcher determines that students study an average of 80 +- 20 (MSD) minutes per week. Assuming these data are normally distributed, what is the z score for students studying 60 minutes per week? Show your work on the paper provided.
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