A 28.0 kg wheel, essentially a thin hoop with radius 0.530 m, is rotating at 424...

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A 28.0 kg wheel, essentially a thin hoop with radius 0.530 m, is rotating at 424...

A 28.0 kg wheel, essentially a thin hoop with radius 0.530 m, is rotating at 424 rev/min. It must be brought to a stop in 25.0 s. (a) How much work must be done to stop it? (b) What is the required average power? Give absolute values for both parts.

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Answer 1

Answer #1

Use the moment of inertia and initial angular speed and work energy principle to find the work done and divide the value of work done by time to find the power as shown below

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Answer 2

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A 28.0 kg wheel, essentially a thin hoop with radius 0.530 m, is rotating at 424...

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A 28.0 kg wheel, essentially a thin hoop with radius 1.00 m, is rotating at 320...

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A 28.0 kg wheel, essentially a thin hoop with radius 0.530 m, is rotating at 424...

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Add Answer to: A 28.0 kg wheel, essentially a thin hoop with radius 0.530 m, is rotating at 424...

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A 28.0 kg wheel, essentially a thin hoop with radius 0.530 m, is rotating at 424...