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Find the useful power output of an elevator motor that lifts a 2500-kg load a height...

Find the useful power output of an elevator motor that lifts a 2500-kg load a height of 35 m in 17 s, if it also increases the speed from rest to 4.25 m/s. Note that the total mass of the counterbalanced system is 10,000 kg--so that only 2500 kg is raised in height, but the full 10000 kg is accelerated.

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