An athlete executing a long jump leaves the ground at a 30 degree angle and travels...

Question

Question

An athlete executing a long jump leaves the ground at a 30 degree angle and travels 8.0 m. What was the takeoff speed?

Answer 1

Answer #1

Solution) Angle , theeta = 30°

X = 8 m

Vo = ?

X = ((Vo^2)(sin(2(theeta))))/(g)

8 = ((Vo^2)(sin(60)))/(9.8)

Vo^2 = (8×9.8)/(sin(60))

Vo^2 = 90.528

Vo = (90.528)^(1/2)

Vo = 9.51 m/s

Answer 2

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