Question

- White light spectrum –

            a.         How does the spectrum of white light differ from the spectrum of hydrogen, neon and

                        sodium?

            b.         What color corresponds to 5.7 x 10^-7 meters? _____________________________

- Hydrogen Emission Spectrum –  There are several lines with colors and 3 lines which are

            white.  The white lines are in the infrared region and not visible.

            a.         Which line in the visible spectrum has the longest wavelength and lowest energy?

                        ______________________

                        

b.         Figure 6.1 in the lab manual represents the Balmer series of emission lines for the hydrogen atom.  Which transition accounts for the emission of a photon with the highest energy? (give n-values that indicate an emission process;  e.g., n=4  n=3)  What color is this line?   

Answer 1

a) Solution: The spectrum of white light consists of a continuous range of colours from red to violet.It forms a visible spectrum. Spectrum of white light is different as it forms a continuous and absorption spectra while that of hydrogen ,neon and sodium is formed due to emission i.e forming a emission spectra.

b) The color corresponding to 5.7 ×10^-7 meters wavelength is Yellow..This can be explained relatively from VIBGYOR and through experimental data.

Hydrogen Emission Spectrum

a) Wavelength is longer and energy is lower for first line of Balmer Series. As the emission occurs from higher states States of Balmer Series wavelength decreases and so the energy gets decreased. This can be calculated by Rydberg Formula.

b) The emission in case of Balmer Series having higher energy will be for Transition from n=infinity to n= 2. Color of this line is Red.