Phosphoric acid is a polyprotic acid (more than one proton that gets ionized) with 3 pK values: pK1=2.15, pK2=6.82 and pK3=12.38. Which molecular species are present at pH 6.82?
mostly H3PO4
[H3PO4]=[H2PO4-]
mostly [H2PO4-]
[H2PO4-]=[HPO42-]
mostly [HPO42-]
[HPO42-]=[PO43-]
mostly [PO43-]
There is are no concentrations provided for the question so it is a question on what stage of deprotonation the phosphoric acid is at
Phosphoric acid is a polyprotic acid (more than one proton that gets ionized) with 3 pK...
Please explain in steps 3.) Calculate the concentrations of all molecular and ionic species and the pH in aqueous solutions that have the following formal compositions: a) 0.05 M acetic acid + 0.1 M sodium acetate; b) 0.2 M boric acid + 0.05 M sodium borate (pK, of boric acid = 9.24); c) 0.5 M hydrochloric acid. Some representative K, and pK, values: Acid Oxalic acid H3PO4 Formic acid Succinic acid Oxalate Acetic acid Succinate H2CO3 H2PO4 NH4+ HCO3 Piperidine...
Phosphoric acid is a triprotic acid in water, ionizing in the following sequential steps: H3PO4+H204H2PO4 +H30+ K. = 7.11 x 10-3 H2PO4 + H20 5 HPO42- +H30+ K. -6.32 x 10-8 HPO42- + H20 PO43- +H30+ K. - 4.5 x 10-13 What is the pH of a 0.20 MH3PO4 solution? 04.09 5.37 2.15 2.84 1.46
Phosphoric acid, H3PO4(aq), is a triprotic acid, meaning that one molecule of the acid has three acidic protons. Estimate the pH, and the concentrations of all species in a 0.500 M phosphoric acid solution. pKa1= 2.16 pKa2 = 7.21 pKa3 = 12.32 What's: H3PO4, H2PO4-, HPO4-2, PO4-3, H+ ,OH- , pH
8. Phosphoric acid H3(PA) is a triprotic molecule that can be present in solution in the following forms. H3(PA), H2(PA)-, H(PA)-2, H(PA)-3 pts) Phosphoric acid HPAIS a tiorotic moiecule that can be presen in soludon in the following foms Hat PA, HaPA HIPAFAY The pK, values for Hi(PA) are the following: pK 2.148 pK2 7.198 pK3 12.375 a) What is the principal form when the solution pH 5.35? b) What is the second most abundant form of TBA at pH...
Phosphoric acid, H3PO4(aq), is a triprotic acid, meaning that one molecule of the acid has three acidic protons. Estimate the pH and the concentrations of all species in a 0.300 M phosphoric acid solution. pKa1 pKa2 pKa3 2.16 7.21 12.32 [H3PO4]= M [H^+]= M [H2PO4 ^−]= M [OH^−]= M [HPO4 ^2−]= M pH= [PO4 ^3−]= M
Phosphoric acid, H,PO (aq), is a triprotic acid, meaning that one molecule of the acid has three acidic protons. Estimate the pH and the concentrations of all species in a 0.150 M phosphoric acid solution. pKq1 2.16 p Kq2 7.21 PK 3 12.32 | | | [H2PO4) = MH*) =( [H,PO,] = M (OH) = (HPO )= M pH = [PO-1=
The pK, values for successive ionization of phosphoric acid are 2.15, 7.21, and 12.35. (a) What weights of NaH2PO4 and Na2HPO4 would be required to prepare 1 L of a buffer solution of pH 7.45 that has an ionic strength of 0.100? (b) Write the equation that specifies that the solution is electrically neutral. (c) Calculate the concentrations of all species in the buffer.
Polyprotic acids have more than one proton to donate to water, therefore have more than one equid constant for proton donation. For phosphoric acid, there is a three-step equilibrium: HAPO+H,O SHPO4 + H30+ H,PO," +H2O 5 HPO - +4,0* HPO,- +H,0 5 PO."-+H,0* Kaj = 7.11 10-3 Ka2 = 6.32 x 10-8 Kaj = 4.5 x 10-13 For all conjugate acid/base pairs: K x K K , where K is for the reaction of the conjugate base in water to...
Orthophosphate (PO4 3- ) is a soluble polyprotic acid capable of protonating/deprotonating up to 3 protons to produce aqueous H3PO4 0 , H2PO4 - , HPO4 2- and PO4 3- . The pKa values of the associated dissociation reactions are as follows: pKa1=2.1; pKa2 = 7.2; and pKa3 = 12.4. Here you are asked to construct the speciation diagram of orthophosphate showing the concentrations of each of the four orthophosphate species in the pH range 1 -14 for a solution...
please help >< Polyprotic acids have more than one proton to donate to water, therefore have more than one equilibrium constant for proton donation. For phosphoric acid, there is a three-step equilibrium: H, PO +H,0 5 H2PO4 + H30* H,PO," +H,0 5 HPO - +H30* HPO 2- +,0 5 PO.- +,0* Kai = 7.11 x 10-3 Ka2 = 6.32 x 10-8 Ka; = 4.5 x 10-13 For all conjugate acid base pairs: K, XKK where K is for the reaction...