At time t = 0, the initial position of an object is x1 = -5.00 m. Three seconds later he is in position x2 = 4.00m and finally moves to position x3 = -8.00m for a total time of seven seconds. The speed Average (in m / s) between position x2 and position x3 is:
The answer is in the images. Page number is mentioned at right top. Here I also calculated total speed of entire path. I have done this extra for better understanding of this type of problem.
At time t = 0, the initial position of an object is x1 = -5.00 m....
A car moves along a straight street. The car’s initial position at time t1 is given by a position vector x! . The car’s later position vector is x2! at time t2. Suppose x1! = 700 miˆ . and x2! =400miˆ. a. If t2 – t1 = 3.0 seconds, what is the car’s average speed (assuming the car only moved in one direction)? b. What was the car’s average velocity?
The following is a position-time graph for an object during a 5.0s time interval Time (s) 8. Which graph of velocity versus time would best represent the object's motion during the same time interval? 띠 Tane n 9. Which graph in diagram 1-36 below represents the motion of an object increasing in velocity? ER) CB) IC) Diegrem 1-36 10. A man walks at a speed of 3.00 m/s for 400 seconds, and then walks at 4.00 m/s for 300 seconds....
Q2-b: A particle position s = 0 m at time t = 0s, then after 2 seconds i.e. at t = 2 s the particle position was at s = 3 m, then after 4 seconds i.e. at t = 6 s the particle position was at s = -1 m. Find the particle average velocity and average speed during the 6 seconds time interval.
An object begins at an initial position of s = -2.0 m. The plot shows the object's velocity in the s-direction as a function of time. Find the object's: a. Displacement (Δs) at t = 9.0 s b. Position (s) at t = 9.0 s c. Average velocity (vs,ave) between t = 0 s and t = 9.0s d. Acceleration (a) at t = 2.0, 6.0, and 8.0 s
An object moves with constant acceleration. At t = 2.50 s, the position of the object is x = 2.00 m and its velocity is v = 4.50 m/s. At t = 7.00 s, v = -12.0 m/s. Find: (a) the position and the velocity at t = 0; (b) the average speed from 2.50 s to 7.00 s, and (c) the average velocity from 2.50 s to 7.00 s.
A particle moves in the xy plane with constant acceleration. At time t=0 s, the position vector for the particle is r=9.70mx^+4.30my^. The acceleration is given by the vector a=8.00m/s^2x^+3.90m/s^2y^. The velocity vector at time t=o s is v=2.80m/sx^ - 7.00m/sy^. What is the magnitude of the position vector at time t= 2.10 s? What is the angle between the position vector and the positive x-axis at time t= 2.10 s?
Consider an object moving along a line with the following velocity and initial position. Assume time t is measured in seconds and velocities have units of m/s. Complete parts (a) through (d) below. Consider an object moving along a line with the following velocity and initial position. Assume time t is measured in seconds and velocities have units of m/s. Complete parts (a) through (d) below. v(t) = -1-2cos for Osts (0) = 0 (**). a. Over the given interval,...
A student measures the velocity of an object moving along a track. At time t = 0 s, the object is moving at a constant 4.0 m/s in the positive x-direction. At time t = 3.0 s, the object begins to slow, stops at t = 5.0 s, and then moves in the opposite direction. At t = 6.0 s, the object as reached a speed of -2.0 m/s. It moves at this speed until the student quits taking data...
A 5.17-kg object passes through the origin at time t = 0 such that its x component of velocity is 4.80 m/s and its y component of velocity is -3.06 m/s. (a) What is the kinetic energy of the object at this time? J (b) At a later time t = 2.00 s, the particle is located at x = 8.50 m and y = 5.00 m. What constant force acted on the object during this time interval? (c) What...
A bal moves from a position of x1=3.4 cm to a position of x2=-4.2 cm durint a time t1=3.0 to t2= 6.1 s 1. total distance 2.displacement 3. averange velocity 4. average speed in the time interval