A car moves along a straight street. The car’s initial position at time t1 is given by a position vector x! . The car’s later position vector is x2! at time t2. Suppose x1! = 700 miˆ . and x2! =400miˆ.
a. If t2 – t1 = 3.0 seconds, what is the car’s average speed (assuming the car only moved in one direction)?
b. What was the car’s average velocity?
A car moves along a straight street. The car’s initial position at time t1 is given...
1. A car moves along a straight street. The car's initial position at time tı is given by a position vector . The car's Iater position vector is at time ta. Suppose 700 mi and x, 400 mi a. If -丸= 3.0 seconds, what is the car's average speed (assuming the car only moved in one direction)? b. What was the car's average velocity?
1. A car moves along a straight street. The car's initial position at time t is given by a position vector T, The car's later position vector is , at time t2 Suppose T700 mi and T - 400 mi . a. If t2-t1 = 3,0 seconds, what is the car's average speed (assuming the car only moved in one direction)? b. What was the car's average velocity? 2. A runner jogs at a stendy pace of 15 km/hr. When...
A bal moves from a position of x1=3.4 cm to a position of x2=-4.2 cm durint a time t1=3.0 to t2= 6.1 s 1. total distance 2.displacement 3. averange velocity 4. average speed in the time interval
At time t = 0, the initial position of an object is x1 = -5.00 m. Three seconds later he is in position x2 = 4.00m and finally moves to position x3 = -8.00m for a total time of seven seconds. The speed Average (in m / s) between position x2 and position x3 is:
Below is a motion diagram for an object that moves along a linear path. The dots represent the position of the object at three subsequent instants, t1, t2, and t3. The vectors v⃗ 21 and v⃗ 32 show the average velocity of the object for the initial time interval, Δt21=t2−t1, and the final time interval, Δt32=t3−t2, respectively. Draw the vector −v→21 and the acceleration vector a⃗ representing the change in average velocity of the object during the total time interval...
8. A student rolls a marble alongside a meterstick to measure
its velocity. At t1 = -2.5 s, its position is x1 = 4.3 cm, and at
t2 = 4.5 s it is at x2 = 18.5 cm. Determine its average velocity
during this time interval.
9. The position of a ball rolling along a straight line is given by
? = 1.8−3.6? +1.5?2, where x is in meters and t is in seconds.
Determine the average velocity of the...
Learning Goal: To practice Tactics Box 4.1 Finding the Acceleration Vector.Part A Below is a motion diagram for an object that moves along a curved path. The dots represent the position of the object at three subsequent instants, t1, t2 and t3. The vectors 1 and t show the average velocity of the object for the initial time interval. Δt1=t2-t1, and the final time interval, Δt=t3-t2. Figure 1 of 1 average velocity of the object during the total time interval Δt=t3-t1 Draw the...
any help would be great!
A car is moving along a straight road. At time t seconds, the position of the car (in feet) is s(t) = 51. Find the average velocity of the car over the time intervals given below. (a) t = 11 to t= 11.1 seconds (b) t = 11 tot = 11.01 seconds (c) t = 11 to t = 11.001 seconds (a) The average velocity of the car over the time interval from t =...
A car travels with constant acceleration along a straight road. It was at the origin and at rest at t1=0 s; its position is x2=155.02 m at t2=7.43 s. What was the car's position at t=2.76 s?
Table 3.1
Time, t (s)
Position, x (m)
tn/t1
Time Squared, t^2 (s^2)
(tn)^2/(t1)^2
xn/x1
t1, 0.40
x1, 0.25
1.0
.16
1
1
t2, 0.80
x2, 0.36
2.0
.64
4
1.4
t3, 1.2
x3, 0.52
3.0
1.4
9
2.1
t4, 1.6
x4, 0.71
4.0
2.6
16
2.8
t5, 2.0
x5, 0.95
5.0
4.0
25
3.8
t6, 2.4
x6, 1.2
6.0
5.8
36
4.8
Linear fit equation for Position Vs. Time: 0.545x - 0.0530
Quadratic fit equation for Position Vs. Time:...