Question

A converging lens (f = 11.0 cm) is held 5.90 cm in front of a newspaper,...

A converging lens (f = 11.0 cm) is held 5.90 cm in front of a newspaper, the print size of which has a height of 2.00 mm. Find (a) the image distance (in cm) and (b) the height (in mm) of the magnified print.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A converging lens (f = 11.0 cm) is held 5.90 cm in front of a newspaper,...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A converging lens (f = 14.0 cm) is held 6.20 cm in front of a newspaper,...

    A converging lens (f = 14.0 cm) is held 6.20 cm in front of a newspaper, the print size of which has a height of 2.20 mm. Find (a) the image distance (in cm) and (b) the height (in mm) of the magnified print.

  • A converging lens (f = 13.2 cm) is held 7.30 cm in front of a newspaper,...

    A converging lens (f = 13.2 cm) is held 7.30 cm in front of a newspaper, the print size of which has a height of 2.04 mm. (a) Find the image distance (in cm), d = cm (b) The height (in mm) of the magnified print. h = mm

  • A converging lens (f = 10.4 cm) is held 8.15 cm in front of a newspaper,...

    A converging lens (f = 10.4 cm) is held 8.15 cm in front of a newspaper, the print size of which has a height of 1.98 mm. (a) Find the image distance (in cm), d = cm (b) The height (in mm) of the magnified print. h = mm

  • A diverging lens (f = –11.0 cm) is located 23.0 cm to the left of a...

    A diverging lens (f = –11.0 cm) is located 23.0 cm to the left of a converging lens (f = 34.0 cm). A 2.50-cm-tall object stands to the left of the diverging lens, exactly at its focal point. (a) Determine the distance of the final image relative to the converging lens. (b) What is the height of the final image (including the proper algebraic sign)?

  • . A diverging lens (f = –11.0 cm) is located 19.0 cm to the left of...

    . A diverging lens (f = –11.0 cm) is located 19.0 cm to the left of a converging lens (f = 30.0 cm). A 2.90-cm-tall object stands to the left of the diverging lens, exactly at its focal point. (a) Determine the distance of the final image relative to the converging lens. (b) What is the height of the final image (including the proper algebraic sign)?

  • 7. Consider a converging lens that has a focal length (f). Which one of these is...

    7. Consider a converging lens that has a focal length (f). Which one of these is correct about the image when the object is placed in front of the lens at a distance of (f/4 )? The image is real, erect, and diminished The image is real, erect, and magnified The image is virtual, inverted, and magnified The image is virtual, erect, and magnified The image is virtual, erect, and has the same size as the object The image is...

  • A 5 cm tall object stands in front of a converging lens with focal length f...

    A 5 cm tall object stands in front of a converging lens with focal length f = 35 cm. The distance between the object and the lens is 10 cm. (a) Give the power of the lens. (b) Calculate the position and height of the image formed. Is the image real or virtual? (c) In the space below clearly produce the ray diagram (at least two of the three rays that form the image). A farsighted person uses spectacles formed...

  • A 2.0 cm tall object is placed 10.0 cm in front of converging lens of focal...

    A 2.0 cm tall object is placed 10.0 cm in front of converging lens of focal length 8 cm. What can you say about the image formed by the lens? de the image is real, magnified and inverted the image is virtual, diminished and inverted O the image is virtual, magnified and upright the image is real, magnified and upright the image is real, diminished and inverted

  • A diverging lens of focal length –30.0 cm is placed 25.0 cm behind a converging lens...

    A diverging lens of focal length –30.0 cm is placed 25.0 cm behind a converging lens of focal length 60.0 cm. A real, upright object of height 2.00 cm is placed 20.0 cm in front of the converging lens. (a) Determine the location of the final image. (Clearly state the location of the final image.) (b) Determine the size and the nature of the final image.

  • A converging lens of focal length 20.0 cm is separated by 50.0 cm from a converging...

    A converging lens of focal length 20.0 cm is separated by 50.0 cm from a converging lens of focal length 5.00 cm. a) Find the position of the final image of an object placed 42.0 cm in front of the first lens. Solve graphically and mathematically. b) If the height of the object is 2.00 cm, what is the height of the final image? c) Is the final image real or virtual? Is it inverted or upright?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT