Question

Part Two:

Create a box and whisker plot and identify the outliers for the following data sets 4 and 5

Data Set 4

12, 72, 10, 13, 9, 11, 13, 12, 8, 15.

Data Set 5

88, 89, 87, 92, 15, 85, 95, 98, 100, 90.

Answer 1

Data set 4:

Following table shows the ordered data set :

S.No.	Data
1	8
2	9
3	10
4	11
5	12
6	12
7	13
8	13
9	15
10	72

Five number summary:

Minimum: 8

First quartile: There are 5 data values. So first quartile will be 3rd data value. Therefore

Median: Median will be average of 5th and 6th data values. Therefore

Third quartile: There are 5 data values. So third quartile will be 8th data value. Therefore

Maximum : 72

Interquartile range:

Fences:

Lower fence:

Upper fence:

Since data value 72 is not within fences so 72 is an outlier.

Following is the box plot

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Data set 5:

Following table shows the ordered data set :

S.No.	Data
1	15
2	85
3	87
4	88
5	89
6	90
7	92
8	95
9	98
10	100

Five number summary:

Minimum: 15

First quartile: There are 5 data values. So first quartile will be 3rd data value. Therefore

Median: Median will be average of 5th and 6th data values. Therefore

Third quartile: There are 5 data values. So third quartile will be 8th data value. Therefore

Maximum : 100

Interquartile range:

Fences:

Lower fence:

Upper fence:

Since data value 15 is not within fences so 15 is an outlier.

Following is the box plot