Question

The function F(x)= x^3/16 - 3*x^4/256 for 0 ≤ x ≤ 4 , 0 for x...

The function F(x)= x^3/16 - 3*x^4/256 for 0 ≤ x ≤ 4 , 0 for x < 0 and 1 for x > 4 is the CDF of a random variable X.

Using R:
a) Using R, create a user-defined function for F in the interval [0,4].

b) Using this F, find the probability that X < 2.5

c) Using F, find the probability that X > 1.5

d) Using F, find the probability that 1.7 < X < 3.4

e) What is the probability density function(in R code) for X between 0 and 4 ?

f) Paste your R script in the following box

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Answer #1

ANSWER::

a)

> fx <- function(x) {x^3/16-3*x^4/256}

b)

> fx(2.5)
[1] 0.5187988

c)

> fx(4)-fx(1.5)
[1] 0.8483887

d)

> fx(3.4)-fx(1.7)
[1] 0.6812949

e)

fx <- expression(x^3/16-3*x^4/256)
> D(f,'x')
3 * x^2/16 - 3 * (4 * x^3)/256

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