Solution :
Given that,
Point estimate = sample mean = = 29.3
sample standard deviation = s = 3.8
sample size = n = 90
Degrees of freedom = df = n - 1 = 89
t /2,df = 1.834
Margin of error = E = t/2,df * (s /n)
= 1.834 * (3.8 / 90)
Margin of error = E = 0.7
The 93% confidence interval estimate of the population mean is,
- E < < + E
29.3 - 0.7 < < 29.3 + 0.7
28.6 < < 30.0
(28.6 , 30.0)
a random sample of 90 observations produced a mean of xbar = 29.3 and s =...
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