A circuit consists of a pure resistance and a coil in series. The power dissipated in...
A circuit consists of a pure resistance and a coil in series. The power dissipated in the pure resistance is 500W and the voltage drop across it is 100V. The power dissipated in the coil is 100W and the drop across it is 50V. Find the resistance and reactance of the coil and the supply voltage. Please explain every step.
Homework Answers
It is a simple series circuit of pure resistance and coil.
Coil can be modelled as a combination of R1 and X1.
Also voltage across resistor and voltage across inductor differ by a phase angle of 90 degree.
Using ohm's law and simple equations of power
calculations,required values are easily obtained.
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A circuit consists of a pure resistance and a coil in series.
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For the given circuit, find the following: The total load resistance of the circuit between circuit...
For the given circuit, find the following:
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The current through each resistor.
The voltage across each resistor.
The power dissipated by each resistor.
The power supplied by the battery.
The terminal voltage, Vab.
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For the given circuit, find the following:
The total load resistance of the circuit between circuit points
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The current through each resistor.
The voltage across each resistor.
The power dissipated by each resistor.
The power supplied by the battery.
The terminal voltage, Vab.
Please be as detailed as possible and explain each
step.
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