Let M denote the mass of Earth and let R denote its radius. The ration g/G at Earth’s surface is
a. R/M
b. M/R
c. M/R^2
d. R^2/M
e. m/R^2
Let M denote the mass of Earth and let R denote its radius. The ration g/G...
2. Assume the earth is a uniform sphere of mass M and radius R. (Its mass-density ρ--M/V is therefore constant.) a) Find the force of gravity exerted on a point mass m located inside the earth, as a function of its distance from the earth's centre. (You may make use of results derived in class for a thin spherical shell.) b) Find the difference in the gravitational potential energy of the mass, between the centre of the earth and the...
If mass of Mars is MMars ≈ 0.11 MEarth, what is the ration of its radius to radius of Earth, RMars/REarth = ?. Gravitational acceleration at the Earth and the Mars surfaces are respectively 9.8 m/s^2 and 3.8 m/s^2 approximately.
A newly discovered planet has twice the mass and three times the radius of the earth. What is the free-fall acceleration at its surface, in terms of the free-fall acceleration g at the surface of the earth? a. 1/9 g b. 2/3 g c. 3/4 g d. 4/3 g E. None of these
7. Given that the mass and radius of the Earth are 5.972x1024 kg and 6371 km, respectively, then the escape velocity of planet Earth-Prime, whose radius is the same as Earth’s but whose mass is 2.0 Earth masses is a) 15.8 km/s b) 15.0 km/s c) 13.7 km/s d) 10.6 km/s e) 23.6 km/s
With M=mass of the disk, m= hanging mass, R=radius of the disk, r=radius of the spool , a= linear acceleration , and α=angular acceleration , which formula gives the torque of the tension force, τ? A. τ=mgr B. τ=mαR C. τ=m(g-a)r D. τ=m(g-a)R E. τ=(M-m)(g-a)R F. None of the above
How far above the surface of the Earth will a person’s weight be reduced to one-quarter its value at the surface? g=Gme/r2 where me is the mass of the Earth, r is the distance from the Earth’s center to the height above Earth and G is the proportionality constant. You will need to look up the mass and radius of the Earth.
How far above the surface of the Earth will a person’s weight be reduced to one-quarter its value at the surface? Hint: g=Gme/r2 where me is the mass of the Earth, r is the distance from the Earth’s center to the height above Earth and G is the proportionality constant. You will need to look up the mass and radius of the Earth.
An object with mass m away from the center of the center of the earth with mass M by the relationship r = h + R where R the radius of the earth and h the object height from the surface of the earth.At any height h, the value of the acceleration earth gravity equal half its value at the surface?
10-3. A 639-kg satellite is in a circular orbit about Earth at a height h = 1.16 x 10^7 m above the Earth’s surface. Find (a) the gravitational force (N) acting on the satellite, (b) the satellite’s speed (m/s) (magnitude of its velocity, not its angular velocity), and (c) the period (h) of its revolution. Caution: The radius of the satellite’s orbit is not just its height above the Earth’s surface. It also includes the radius of the Earth. The...
Questions 17-20 A small object of mass m is launched from the surface of the Earth with a speed of to in a direction perpendieular to the Earths surface. 17. What is the total mechanical energy of the object at its starting point in terms of m, uo. the radius of the Earth R, the mas of the Earth M, and the gravitational constant G