Use the worked example above to help you solve this problem. In a crash test, a...
Use the worked example above to help you solve this problem. In a crash test, a car of mass 1.44 103 kg collides with a wall and rebounds as shown in the figure. The initial and final velocities of the car are vi = -15.2 m/s and vf = 2.11 m/s, respectively. If the collision lasts for 0.153 s, find the following. (a) the impulse delivered to the car due to the collision kg · m/s (b) the size of and direction of the average force exerted on the car (Indicate the direction with the sign of your answer.) N
Homework Answers
(a) The impulse delivered to the car due to the collision.
Impulse = Change in momentum
ANSWER: 
=============================
(b) The size of and direction of the average force exerted on the car (Indicate the direction with the sign of your answer.) N
Impulse = Average force * time
Direction is same as direction of final velocity
ANSWER: 
===============================
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Use the worked example above to help you solve this problem. In
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1. Automobile collision[Page 171 ( of text book): Note the threshold conditions described and study the...
1. Automobile collision[Page 171 ( of text book):
Note the threshold conditions described and study the problem
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use the numbers given in the problem; use your own set of numbers;
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1. Automobile collision[Page 171 ( of text book):
Note the threshold conditions described and study the problem
given there. Then apply the momentum impulse equation to determine
the force and acceleration a person of your mass and size (do not
use the numbers given in the problem; use your own set of numbers;
must be different for each student) will experience in a head-on
collision and discuss the injury caused by the collision. Also
comment on what type of collision...
PRACTICE IT Use the worked example above to help you solve this problem. A golf ball with mass 5.70 x 10 2 kg is struck with a club as shown in the figure above. The force on the ball varies from zero when contact is made up to some maximum value (when the ball is maximally deformed) and then back to zero when the ball leaves the club, as in the graph of force vs. time in the figure below....
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