The results for daily intakes of milk (in ounces) for ten randomly selected people were xˉ=18.23...
The results for daily intakes of milk (in ounces) for ten randomly selected people were xˉ=18.23 and s=6.11. Find a 99% confidence interval for the population standard deviation σ. Assume that the distribution of ounces of milk intake daily is normally distributed.
What is the margin of error?
Homework Answers
)solution
Given that,
= 18.23
s =6.11
n = 10
Degrees of freedom = df = n - 1 =10 - 1 = 9
At 99% confidence level the t is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
t
/2 df = t0.005,9 = 3.250 ( using student t table)
Margin of error = E = t/2,df
* (s /
n)
= 3.250* ( 6.11/
10) = 6.28
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